SolidJS•14mo ago

splitProps default value

how can i define the default value of a prop with split prop, for example the "loader" prop is optional i want tha make it true by default, but it is undefined

const [ local, rest ] = splitProps(props, ['loader'])

const [ local, rest ] = splitProps(props, ['loader'])

yes i can use a ternary and validate the value but i want to set the default value if it is possible

  local.loader ? true : false

  local.loader ? true : false

1 Reply

REEEEE•14mo ago

use mergeProps

props = mergeProps(props, {loader: false})
const [ local, rest ] = splitProps(props, ['loader'])

props = mergeProps(props, {loader: false})
const [ local, rest ] = splitProps(props, ['loader'])

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splitProps default value