Drizzle Team•13mo ago

Dealing with type safety

I am trying to do something like this: if (result.length === 0) { throw new Error(No user with id ${id} found.); } return result[0]; But typescript complains that { .... } | undefined is assignable to { ... }. How could i fix that? Should the if already deal with the case in which result is undefined?

1 Reply

Angelelz•13mo ago

You have to assign it to a variable first to make the TS compiler happy

  const value = result[0]
  if (!value) {
                throw new Error(No user with id ${id} found.);
   }

  return value;

  const value = result[0]
  if (!value) {
                throw new Error(No user with id ${id} found.);
   }

  return value;

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Dealing with type safety