$table->contentGrid()
hi please ->contentGrid() must be in ressource or in list page?
because don't want to work for me
i need specific syntaxe?
4 Replies
I think it should go on the page class, in the
table() method. Can you show the code you have tried?
Oh, looks like it should work in the resource too...public static function table(Table $table): Table
{
return $table
->contentGrid([
'md' => 2,
'xl' => 3,
])
->columns([
TextColumn::make('code')->sortable()
->searchable(),
ImageColumn::make('image')
->disk('public_uploads')
->label('Photo')
->width(100)
->height(100)
->defaultImageUrl(url('images/default-boardtypes.png')),
TextColumn::make('region_name')->sortable()
->searchable()
->label('Region'),
TextColumn::make('ville_name')->sortable()
->searchable()
->label('Ville - Commune')
->description(fn ($record) => ' ' . $record->commune_name .' ' ),
TextColumn::make('adresse')
->searchable()
->label('Adresse'),
TextColumn::make('type')->sortable()
->searchable()
->label('Type'),
TextColumn::make('face')->sortable()
->label('Face')
->description(fn ($record) => ' ' . $record->libre .' ' ),
])
If you add a random layout component such as Grid or Panel to it, even if it's empty, the contentGrid will then work
I must do it inside the column ?
thanks its work