Db race condition

Is there any tool with drizzle that can help with handling race conditions?
17 Replies
micaww
micaww•16mo ago
that's incredibly vague. what problem are you trying to solve? likely outside the scope of drizzle though. depends on the db you're using and application requirements
Nickolaki
NickolakiOP•16mo ago
I have an endpoint that create a db journey for a customer. A customer should only ever have 1 journey.
export async function POST(req: Request) {
const body = (await req.json()) as CreateJourneyRequest;

const existingJourney = await db.transaction(async (tx) => {
const result = await tx.query.journeys.findFirst({
with: {
products: {
with: {
product: true,
},
},
},
where: (journeys, { eq }) =>
eq(journeys.customer_emailAddress, body.emailAddress),
});

return result;
});

if (existingJourney)
return NextResponse.json(existingJourney);
}

const journeyId = uuidv4();

const newJourney = {
id: journeyId,
customer_firstName: body.firstName,
customer_lastName: body.lastName,
customer_emailAddress: body.emailAddress,
completed: false,
currentstep: "review",
};

await db.transaction(async (tx) => {
console.log(Date.now(), "Inserting New Journey");
await tx.insert(journeys).values(newJourney);
console.log(Date.now(), "Finished Inserting New Journey");

const productsToLink = await tx.query.products.findMany({
where: (products) => inArray(products.name, body.initialProducts),
});

const journeysProductsToInsert = productsToLink.map((product) => ({
journeyId,
productId: product.id,
}));

await tx.insert(journeysToProducts).values(journeysProductsToInsert);
});
}
export async function POST(req: Request) {
const body = (await req.json()) as CreateJourneyRequest;

const existingJourney = await db.transaction(async (tx) => {
const result = await tx.query.journeys.findFirst({
with: {
products: {
with: {
product: true,
},
},
},
where: (journeys, { eq }) =>
eq(journeys.customer_emailAddress, body.emailAddress),
});

return result;
});

if (existingJourney)
return NextResponse.json(existingJourney);
}

const journeyId = uuidv4();

const newJourney = {
id: journeyId,
customer_firstName: body.firstName,
customer_lastName: body.lastName,
customer_emailAddress: body.emailAddress,
completed: false,
currentstep: "review",
};

await db.transaction(async (tx) => {
console.log(Date.now(), "Inserting New Journey");
await tx.insert(journeys).values(newJourney);
console.log(Date.now(), "Finished Inserting New Journey");

const productsToLink = await tx.query.products.findMany({
where: (products) => inArray(products.name, body.initialProducts),
});

const journeysProductsToInsert = productsToLink.map((product) => ({
journeyId,
productId: product.id,
}));

await tx.insert(journeysToProducts).values(journeysProductsToInsert);
});
}
What I'm seeing is that If I call this endpoint twice in very fast succession. 1st request will not get an existingJourney and proceeed to insert one. 2nd request will query existingJourney but will still be undefined as the inserted one from request 1 is not complete or committed (not sure how it works). I don't know if I'm remotely using db transactions for what they are supposed to be for. Has that given you context? 🙂 @Raphaël M (@rphlmr) ⚡ Boss, can you help me with this? 😘
rphlmr âš¡
rphlmr ⚡•16mo ago
I would first try to wrap all in the same transaction? A transaction is to tell: do all of this or rollback if one of the request fail Is this request fired from UI? Do you have disabled submit button? One thing I don't understand: do you have a unique constraint saying that one user could only have 1 journey? because even on race conditions there should be only one winner. The slowest would return an error.
Nickolaki
NickolakiOP•16mo ago
I do not its simply a text property in the table, so maybe that's what I should do
rphlmr âš¡
rphlmr ⚡•16mo ago
For cases where you can insert multiple rows (1:n like payment), you have to go on the idempotent way (client send an idempotent key with every request, preventing double fire to write twice) Can you share it? or just a quick example of your shcemas?
Nickolaki
NickolakiOP•16mo ago
export const journeys = pgTable("journey", {
id: uuid("id").defaultRandom().primaryKey(),
customer_firstName: text("customer_firstName").notNull(),
customer_lastName: text("customer_lastName").notNull(),
customer_emailAddress: text("customer_emailAddress").notNull(),
currentstep: text("currentstep").notNull(),
});
export const journeys = pgTable("journey", {
id: uuid("id").defaultRandom().primaryKey(),
customer_firstName: text("customer_firstName").notNull(),
customer_lastName: text("customer_lastName").notNull(),
customer_emailAddress: text("customer_emailAddress").notNull(),
currentstep: text("currentstep").notNull(),
});
Nothing stopping a user with email "[email protected]" to have 2 journeys atm (I don't want that)
rphlmr âš¡
rphlmr ⚡•16mo ago
So you are okay if a user has 2 journeys?
Nickolaki
NickolakiOP•16mo ago
Na I don't want them to only 1 So would a unique col sort this?
rphlmr âš¡
rphlmr ⚡•16mo ago
you can add customer_id has a reference to this table too or maybe these data are not related to a user table?
Nickolaki
NickolakiOP•16mo ago
I currently don't have a user table 😛
rphlmr âš¡
rphlmr ⚡•16mo ago
ok I see, it's just a 'save a given customer payload attached to a journey'
Nickolaki
NickolakiOP•16mo ago
Yes exactly The intresting thing about changing the col to unique. I wonder if i will still run into the issues I guess you can't, ill do some testing
rphlmr âš¡
rphlmr ⚡•16mo ago
With unique it should add the missing constraint I would try:
export async function POST(req: Request) {
const body = (await req.json()) as CreateJourneyRequest;

const result = await db.transaction(async (tx) => {
const existingJourney = await tx.query.journeys.findFirst({
with: {
products: {
with: {
product: true,
},
},
},
where: (journeys, { eq }) =>
eq(journeys.customer_emailAddress, body.emailAddress),
});

if (existingJourney) {
await tx.rollback()
return NextResponse.json(existingJourney);
}

const journeyId = uuidv4();

const newJourney = {
id: journeyId,
customer_firstName: body.firstName,
customer_lastName: body.lastName,
customer_emailAddress: body.emailAddress,
completed: false,
currentstep: "review",
};

console.log(Date.now(), "Inserting New Journey");
await tx.insert(journeys).values(newJourney);
console.log(Date.now(), "Finished Inserting New Journey");

const productsToLink = await tx.query.products.findMany({
where: (products) => inArray(products.name, body.initialProducts),
});

const journeysProductsToInsert = productsToLink.map((product) => ({
journeyId,
productId: product.id,
}));

await tx.insert(journeysToProducts).values(journeysProductsToInsert);

return NextResponse.json({ success: true, journeyId });
});

return result;
}
export async function POST(req: Request) {
const body = (await req.json()) as CreateJourneyRequest;

const result = await db.transaction(async (tx) => {
const existingJourney = await tx.query.journeys.findFirst({
with: {
products: {
with: {
product: true,
},
},
},
where: (journeys, { eq }) =>
eq(journeys.customer_emailAddress, body.emailAddress),
});

if (existingJourney) {
await tx.rollback()
return NextResponse.json(existingJourney);
}

const journeyId = uuidv4();

const newJourney = {
id: journeyId,
customer_firstName: body.firstName,
customer_lastName: body.lastName,
customer_emailAddress: body.emailAddress,
completed: false,
currentstep: "review",
};

console.log(Date.now(), "Inserting New Journey");
await tx.insert(journeys).values(newJourney);
console.log(Date.now(), "Finished Inserting New Journey");

const productsToLink = await tx.query.products.findMany({
where: (products) => inArray(products.name, body.initialProducts),
});

const journeysProductsToInsert = productsToLink.map((product) => ({
journeyId,
productId: product.id,
}));

await tx.insert(journeysToProducts).values(journeysProductsToInsert);

return NextResponse.json({ success: true, journeyId });
});

return result;
}
await tx.rollback() added in the if + wrapping all in the same transaction
rphlmr âš¡
rphlmr ⚡•16mo ago
Then, transaction behavior config exists too: https://orm.drizzle.team/docs/transactions (end of page). Not sure if it is required and what to change from the default
Nickolaki
NickolakiOP•16mo ago
Yeah the unique thing seems to have solved it. Will try without transaction too to see if its even needed
rphlmr âš¡
rphlmr ⚡•16mo ago
I would suggest to keep transaction when you insert related things, it's better to wrap that in transaction to prevent inconsistent insert
Nickolaki
NickolakiOP•16mo ago
True, thank you bro
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