How can I ->fill() a FileUpload field?
I tried giving the path to the file, no help. Any way to do this?
2 Replies
Not sure, but I think you need just the filename. Check what's in your DB already for some examples.
My FileUpload doesn't know which directory it should upload the file to (I am manually uploading the file). So I am also passing the dir next to file name
like this: x/1/filename
No help though
After filling the form, the form data of the field is an empty array btw