Is there any scenario where batch wouldn't be fully synchronize?
In that once the call to batch(() => { }) completes all signals inside that have been set can be read . i.e. there is no setImmediate/setTimeout/queueMicrotask in the path?
2 Replies
well if you have
batch inside of another batch it won't run any effects yet
and other similar nestings
but overall the system is synchronous
and it doesn't use any setImmediate/setTimeout/queueMicrotask scheduling
Also batch only prevents dependent computations to run, but the values of signals, and dependent memos will give you the updated value even if read during batchhmmm interesting.. I was thinking there might be scenarios where batch would delay the processing but batch within batch might be responsible for the issue I'm seeing, need to get a playground sorted