SolidJS•2y ago

delay execution of createEffect.

I have a use case where I want one of my createEffect to be called before another . Currently they are called one after the other. I want to swap the executing sequence.

13 Replies

AbrinzerOP•2y ago

Is it possible to do that. Or I am trying something weird over here. I have a very valid use case though.

REEEEE•2y ago

Would help to see some code?

Unknown User•2y ago

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AbrinzerOP•2y ago

createEffect(() => {
        if (someCondition1) {
            setQuantity(0);
        }
    });
    createEffect(() => {
        if (someCondition2) {
            setQuantity(orderFlow.quantity);
        }
    });

createEffect(() => {
        if (someCondition1) {
            setQuantity(0);
        }
    });
    createEffect(() => {
        if (someCondition2) {
            setQuantity(orderFlow.quantity);
        }
    });

no way to handle it without timer ?

Unknown User•2y ago

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REEEEE•2y ago

So you want the condition2 effect to run first?

AbrinzerOP•2y ago

Yes correct condition1 to run first.

Unknown User•2y ago

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AbrinzerOP•2y ago

both the condition can be true at the same time. I have not added the complete snippet here. Basically I want to keep them in separate effects to avoid unnecessary computation. But thanks I will look for a settimeout as a solution for now.

Unknown User•2y ago

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AbrinzerOP•2y ago

😢 I don't want to use it . will find a better way eventually . Thanks for your help

REEEEE•2y ago

The only other way is to have a third temporary signal that you update after the first condition and the effect for the second condition reads it

AbrinzerOP•2y ago

aah that makes sense

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delay execution of createEffect.