C#•2y ago

❔ Problem with image hosting API

Hello, I tried to upload an image to an image hosting API but no matter what I do I get the following error : System.Net.WebException: 'The remote server returned an error: (400) Bad Request.' (see screenshot). Code :

C#
   MemoryStream stream = new MemoryStream(); // Stream that will contain the image bytes (can't upload an image straight to SQL db)
            productImage.Image.Save(stream, System.Drawing.Imaging.ImageFormat.Png); // saves the image to byte in the object "stream"
            byte[] picture = stream.ToArray();
            string picture64 = Convert.ToBase64String(picture);

            using (WebClient wc = new WebClient()) // API pour upload l'image sur un serveur et foutre le lien dans la db
            {
                string URL = "https://thumbsnap.com/api/upload";
                string parameters = "key=censored&media=" + picture64;
                wc.Headers[HttpRequestHeader.ContentType] = "multipart/form-data";
                string htmlResult = wc.UploadString(URL, parameters);
            }

C#
   MemoryStream stream = new MemoryStream(); // Stream that will contain the image bytes (can't upload an image straight to SQL db)
            productImage.Image.Save(stream, System.Drawing.Imaging.ImageFormat.Png); // saves the image to byte in the object "stream"
            byte[] picture = stream.ToArray();
            string picture64 = Convert.ToBase64String(picture);

            using (WebClient wc = new WebClient()) // API pour upload l'image sur un serveur et foutre le lien dans la db
            {
                string URL = "https://thumbsnap.com/api/upload";
                string parameters = "key=censored&media=" + picture64;
                wc.Headers[HttpRequestHeader.ContentType] = "multipart/form-data";
                string htmlResult = wc.UploadString(URL, parameters);
            }

62 Replies

Angius•2y ago

First and foremost, use HttpClient not WebClient. The latter is obsolete and should not be used And the API wants a POST request with form-data content Not data sent as a query string

KaedrickOP•2y ago

Thank you I'm gonna change webclient to httpclient, but I don't get the part about the POST request (sry beginner here)

Angius•2y ago

HTTP requests can have different types and send data in various ways GET is for getting, POST is for sending, PATCH for updating, etc The data can be sent as a query string like ?foo=1&bar=hello, which is used for GET requests There are other ways, like multipart/form-data that supports sending files Or application/json that lets you send structured data

Angius•2y ago

The API docs say

KaedrickOP•2y ago

okay uhh sorry just got back, imma try to understand it all yeah I don't get it at all lol I have no clue where to start or even what to do with my code

Angius•2y ago

tl;dr is, you need to send a POST request with multipart/form-data data

Angius•2y ago

https://makolyte.com/csharp-how-to-send-a-file-with-httpclient/

MAKOLYTE

C# - How to send a file with HttpClient | MAKOLYTE

Shows how to send a file in a multipart/form-data request using HttpClient by loading it into a MultipartFormDataContent object

Angius•2y ago

Like in this code, except you'd add one more field to the formdata The field with your API key

KaedrickOP•2y ago

tyvm I'll try to make it work somehow <:br_laugh:742854844301312031>

Angius•2y ago

Yeah, feel free to ask again if the code still doesn't want to work

KaedrickOP•2y ago

I still can’t get it to work lol I have no clue how any of this works, I’ll just get some sleep and watch a few tutorials tomorrow I guess Thanks a lot btw

Angius•2y ago

No problem, anytime 👌

Accord•2y ago

Was this issue resolved? If so, run /close - otherwise I will mark this as stale and this post will be archived until there is new activity.

KaedrickOP•2y ago

Still not fixed no I feel like this is way above my very beginner level lol

Angius•2y ago

Show your current code We'll see what's up

KaedrickOP•2y ago

I deleted most of it to try and start from the beginning, but my problem is with this : https://makolyte.com/csharp-how-to-send-a-file-with-httpclient/ In this example, he sends a file from a predefined path, which is not what I want, I want to send an image that the user chooses from his computer, and secondly, he sends it to a server while I am trying to just use an image hosting API, which I don't know how to change for my usage

MAKOLYTE

C# - How to send a file with HttpClient | MAKOLYTE

Shows how to send a file in a multipart/form-data request using HttpClient by loading it into a MultipartFormDataContent object

KaedrickOP•2y ago

I'll post code when I make some progress lol

Angius•2y ago

I want, I want to send an image that the user chooses from his computer

So get the path to the file from the user

he sends it to a server while I am trying to just use an image hosting API

Where do you believe does the API run? localhost:6001 and https://mycoolwebsite.com are the same thing, fundamentally

KaedrickOP•2y ago

yeah lol I know it's from a server but he just hosts it to some localhost link and not using an API with the key etc so idk how to proceed Is there any way to get a file path automatically from a file selection dialog ?

Angius•2y ago

That's actually what the file dialog gives you, the path And the link to localhost is no different than the link to the API

KaedrickOP•2y ago

Angius•2y ago

Literally the same exact thing

KaedrickOP•2y ago

yeah I know but where does the key go then

Angius•2y ago

Into the form data

MODiX•2y ago

Angius#1586

Like in this code, except you'd add one more field to the formdata

Quoted by

<@!85903769203642368> from #❔ Problem with image hosting API (click here)

React with ❌ to remove this embed.

KaedrickOP•2y ago

okay thanks Imma try to understand it all because even syntax is complicated to me lol i'll get back to you, tyvm hey uh I'm confused about something

KaedrickOP•2y ago

Angius•2y ago

Shoot $scopes

MODiX•2y ago

scope A {
  thing a;
  scope B {
    thing b;
  }
}

scope A {
  thing a;
  scope B {
    thing b;
  }
}

thing a is available in scope A and scope B thing b is available only in scope B

KaedrickOP•2y ago

how do I access this variable if it's in a private class ? I'm pretty sure I can't but it's private by default and I4m not sure changing it is a good idea

Angius•2y ago

Just place it on the class level

class Foo
{
    private int _num;

    private void SomeMethod()
    {
        _num = 69420;
    }

    private void SomeOtherMethod();
    {
        Console.WriteLine($"Num is {_num}");
    }
}

class Foo
{
    private int _num;

    private void SomeMethod()
    {
        _num = 69420;
    }

    private void SomeOtherMethod();
    {
        Console.WriteLine($"Num is {_num}");
    }
}

KaedrickOP•2y ago

very confused as in how to do that here

Angius•2y ago

Just put the variable on the class level

KaedrickOP•2y ago

but if I do that it won't recognize productPicture.Filename; anymore

Angius•2y ago

private string filePath on the class level

KaedrickOP•2y ago

ohhhhhhhh

Angius•2y ago

filePath = productPicture.Filename in one method var filePath = filePath in the other Or just... use the class-level filePath

KaedrickOP•2y ago

I thought I had it but no, I'm dense I think

Angius•2y ago

Angius•2y ago

See my edits in lime green

KaedrickOP•2y ago

woah it works tyvm, just trying to understand, what's the "_" for ?

Angius•2y ago

Just a naming convention Private fields have the _ in front Mostly for use in the constructors With _

class Foo
{
    private int _foo;
    public Foo(int foo)
    {
        _foo = foo;
    }
}

class Foo
{
    private int _foo;
    public Foo(int foo)
    {
        _foo = foo;
    }
}

Without _

class Foo
{
    private int foo;
    public Foo(int foo)
    {
        this.foo = foo;
    }
}

class Foo
{
    private int foo;
    public Foo(int foo)
    {
        this.foo = foo;
    }
}

KaedrickOP•2y ago

okay I think I get it thanks 🙂 so in the page you sent me to send the image to an API, regarding this section :

 
var filePath = @"C:\house.png";

using (var multipartFormContent = new MultipartFormDataContent())
{
    //Load the file and set the file's Content-Type header
    var fileStreamContent = new StreamContent(File.OpenRead(filePath));
    fileStreamContent.Headers.ContentType = new MediaTypeHeaderValue("image/png");

    //Add the file
    multipartFormContent.Add(fileStreamContent, name: "file", fileName: "house.png");

 
var filePath = @"C:\house.png";

using (var multipartFormContent = new MultipartFormDataContent())
{
    //Load the file and set the file's Content-Type header
    var fileStreamContent = new StreamContent(File.OpenRead(filePath));
    fileStreamContent.Headers.ContentType = new MediaTypeHeaderValue("image/png");

    //Add the file
    multipartFormContent.Add(fileStreamContent, name: "file", fileName: "house.png");

I'm not sure how to proceed since "house.png" has to be the selected file name here, and that "image/png" should be "image/whatever the chosen image format is" woops not sure why it quoted the c# part too

Angius•2y ago

$codegif

MODiX•2y ago

https://cdn.discordapp.com/attachments/364492811489509376/892176158312001586/code.gif

Angius•2y ago

You need cs not c# And you can get the MIME type from the extension

MODiX•2y ago

Angius#1586

REPL Result: Success

var file = "house.png";
var mime = $"image/{file.Split('.')[^1]}";
mime

var file = "house.png";
var mime = $"image/{file.Split('.')[^1]}";
mime

Result: string

image/png

image/png

Compile: 510.352ms | Execution: 41.514ms | React with ❌ to remove this embed.

KaedrickOP•2y ago

okay that actually is cool, and for once I understand lol thanks one more thing before I go to sleep and do the rest tommorow how do I get the chosen file name, since "productPicture.FileName" actually returns the picture's whole path and not just its name ?

Angius•2y ago

You can split by the path separator and take the last chunk Or you can use Uri class, I believe Or maybe the Path class One of the two The constructor will take the whole path, and then you'll be able to take whatever from the object

KaedrickOP•2y ago

so if the full path is : C:\Users\secret\OneDrive\Images\secret.png how do I split it so it always takes what comes after the last "" ? *the last " \ "

MODiX•2y ago

Angius#1586

REPL Result: Success

@"C:\Users\secret\OneDrive\Images\secret.png".Split('\\')[^1]

@"C:\Users\secret\OneDrive\Images\secret.png".Split('\\')[^1]

Result: string

secret.png

secret.png

Compile: 470.377ms | Execution: 35.245ms | React with ❌ to remove this embed.

Angius•2y ago

Like this

MODiX•2y ago

Kaedrick#5670

REPL Result: Success

@"C:\secret\OneDrive\secret.png".Split('\\')[^1]

@"C:\secret\OneDrive\secret.png".Split('\\')[^1]

Result: string

secret.png

secret.png

Compile: 447.716ms | Execution: 36.233ms | React with ❌ to remove this embed.

KaedrickOP•2y ago

ok it works even if there's less " \ " in the path

Angius•2y ago

[ a,  b,  c,  d,  e ]
  0   1   2   3   4
 ^5  ^4  ^3  ^2  ^1

[ a,  b,  c,  d,  e ]
  0   1   2   3   4
 ^5  ^4  ^3  ^2  ^1

KaedrickOP•2y ago

perfect tyvm!

Angius•2y ago

With ^ you can index from the end

KaedrickOP•2y ago

ohhh tyvm!! can you explain why there's 2 \ ? just to be sure i understand in (' \ ') ffs it won't let me lol

Angius•2y ago

\ is the escape character So '\' is treated as "character delimiter, then literal apostrophe" A closing character delimiter is, thus, missing '\\' is "character delimiter, literal backslash, character delimiter"

KaedrickOP•2y ago

oh okay! thank you so much you were so helpful I feel like maybe tomorrow or the day after I'll have this damn API upload thing working <:gx_Sunglasses_cry:750469526667264051> but for now, some sleep good night sir

Angius•2y ago

'Night

Accord•2y ago

Was this issue resolved? If so, run /close - otherwise I will mark this as stale and this post will be archived until there is new activity.

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❔ Problem with image hosting API