SolidJS•3y ago

storing a function inside a store

is it currently possible to store a function inside a store? it seems like they are being called immediately when I enter them in a store atm.

  const [state, setState] = createStore<{ test?: () => number }>({
    test: undefined,
  });

  const test = () => performance.now();
  setState('test', test);
  console.log(typeof test === typeof state.test) // logs false
  console.log(state.test, test); // logs 373409 () => performance.now()
  setTimeout(() => console.log(state.test, test()), 1000) // logs 373409 374409

  const [state, setState] = createStore<{ test?: () => number }>({
    test: undefined,
  });

  const test = () => performance.now();
  setState('test', test);
  console.log(typeof test === typeof state.test) // logs false
  console.log(state.test, test); // logs 373409 () => performance.now()
  setTimeout(() => console.log(state.test, test()), 1000) // logs 373409 374409

https://playground.solidjs.com/anonymous/a8dcab94-f01e-48f0-9959-432cc6152de7

Solid Playground

Quickly discover what the solid compiler will generate from your JSX template

6 Replies

Unknown User•3y ago

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bigmistqkeOP•3y ago

it seems to be solved easily by doing setState('test', () => test); 🖇️ I thought I would get type-errors, but ts doesn't complain aa realize now why they are called immediately, because a function is also used as a storesetter.

thetarnav•3y ago

https://playground.solidjs.com/anonymous/a993922c-5ca5-4f49-8a07-d695f93b4351

Solid Playground

Quickly discover what the solid compiler will generate from your JSX template

thetarnav•3y ago

too late, dammit

bigmistqkeOP•3y ago

still learned a thing: didnt know how to do optional function call before

Unknown User•3y ago

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storing a function inside a store