When using array sort, how to ignore the table header?

function sortTable(headerClicked, column) {
    tableContainerRows = tableContainer.querySelectorAll('tr');

    const rowsDuplicate = Array.from(tableContainerRows);

    rowsDuplicate.sort(function (rowA, rowB) {
        console.log(rowA, rowB);

        // Get the content of cells
        const cellA = rowA.querySelectorAll('td')[column].innerHTML;
        console.log(cellA);
        const cellB = rowB.querySelectorAll('td')[column].innerHTML;
        console.log(cellB);
    })
}

function sortTable(headerClicked, column) {
    tableContainerRows = tableContainer.querySelectorAll('tr');

    const rowsDuplicate = Array.from(tableContainerRows);

    rowsDuplicate.sort(function (rowA, rowB) {
        console.log(rowA, rowB);

        // Get the content of cells
        const cellA = rowA.querySelectorAll('td')[column].innerHTML;
        console.log(cellA);
        const cellB = rowB.querySelectorAll('td')[column].innerHTML;
        console.log(cellB);
    })
}