C#•3y ago

FizzBuzz as short as possible

With a little help from StackOverflow I came up with this:

List<string> testList = new List<string>();
testList.Add(Enumerable.Range(1, 200)
                    .Select(n => n % 15 == 0 ? "FizzBuzz"
                               : n % 3 == 0 ? "Fizz"
                               : n % 5 == 0 ? "Buzz"
                               : n.ToString()).ToString());

List<string> testList = new List<string>();
testList.Add(Enumerable.Range(1, 200)
                    .Select(n => n % 15 == 0 ? "FizzBuzz"
                               : n % 3 == 0 ? "Fizz"
                               : n % 5 == 0 ? "Buzz"
                               : n.ToString()).ToString());

Now it adds only one element though, which is "System.Linq.Enumerable+SelectRangeIterator'1[System.String]". How do I get this expression to have one list object for each number?

3 Replies

Tvde1•3y ago

string.Join(
    Environment.NewLine,
    Enumerable.Range(1, 200)
        .Select(n => n % 15 == 0 ? "FizzBuzz"
            : n % 3 == 0 ? "Fizz"
            : n % 5 == 0 ? "Buzz"
            : n.ToString()));

string.Join(
    Environment.NewLine,
    Enumerable.Range(1, 200)
        .Select(n => n % 15 == 0 ? "FizzBuzz"
            : n % 3 == 0 ? "Fizz"
            : n % 5 == 0 ? "Buzz"
            : n.ToString()));

TurwaithOP•3y ago

Thanks, found a different solution in the meantime that works as well:

List<string> result = 

            Enumerable.Range(1, 200)
                    .Select(n => n % 3 == 0 && n % 5 == 0 ? "FizzBuzz"
                               : n % 3== 0 ? "Fizz"
                               : n % 5== 0 ? "Buzz"
                               : n.ToString()).ToList();

List<string> result = 

            Enumerable.Range(1, 200)
                    .Select(n => n % 3 == 0 && n % 5 == 0 ? "FizzBuzz"
                               : n % 3== 0 ? "Fizz"
                               : n % 5== 0 ? "Buzz"
                               : n.ToString()).ToList();

Angius•3y ago

string.Join(
    '\n',
    Enumerable.Range(1, 200)
        .Select(n => (n % 3, n % 5) switch {
    (0, 0) => "FizzBuzz",
    (0, _) => "Fizz",
    (_, 0) => "Buzz",
    _ => $"{n}"
});

string.Join(
    '\n',
    Enumerable.Range(1, 200)
        .Select(n => (n % 3, n % 5) switch {
    (0, 0) => "FizzBuzz",
    (0, _) => "Fizz",
    (_, 0) => "Buzz",
    _ => $"{n}"
});

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FizzBuzz as short as possible