19 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.1/6 is what i got
There's no closed circuit at all....there won't be any current flow right?
S 2 is closed
Yeah still
Circuit is broken at fully filled capacitors
yes but the potentials across the C2 30 ohm and 10V should be same as the potential across C1 and 70ohm right
Ah right
wdym both circuits are closed
5/30
1/6
shouldnt it be the ans
since all capacitor will be in steady state
What how
After the switch is closed the charged capacitors will behave like batteries and the uncharged one becomes short circuited
only 1 capacitor not in steady state
we will only take 30 ohm in to acc no?
what
look
first S1 is closed for long time so all C in steady state
wait a sec
nvm idk
what why?
Potential diff across the same points is the same
Same logic used in parallel circuits
oh u taking them as a whole ic
where did 130 and 4 come from in right most wire
100 and 30 are in series and then the capacitors were giving emf in the opposite direction of the battery so 5-0.5-0.5
ah ic
still
wont they be in steady state so no current passes through?
if u say they will discharge , can they even discharge when battery there?
When you close the switch S1 why is the current flowing werent they in steady state before.When the system changes the steady state will be disturbed and it will want to go towards another steady state
Yes
ahh ic