Zumdahl kineticsmarathon
Idk ismein marathon wale question mein first table or second table dono hin bilkul alag se lag rhen h...dono ka r.o.r. hin alag h...so idk how to even get at the first question done...sorry feeling dumb 😕
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@Dexter
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592
Paanch sow bayanveyyy
this one?
which que in it?
Marathon
92?
Yh
this whole
That one only
a is asking to determine the rate law right so
So!?
so wait no lemme type out im having confusions
I just wrote chx3 to the power a * y to the power b *k as the ror
im also in mid of this chap only
But I am at the end...
Of my jee prep😭🥲and still having such silly
Confusions
we can get tht its first order rxn
How first ordrr
what confusion
because of the given data
calculate slope
its linear relation
Wow how did u calculate slope for every 2 different vals I m getting the different ans
which question
i to applied from how i solved of the ques i did wait ill show
Marathon question
...question no. 92
use only experiment once
Y y
then use second
TvT
The linear relationship indicates that as time increases, ln[CH₃X] decreases at a constant rate.
this is for the first order
so thts why it is first order one
But I don't think it's of the first order
how
Moreover the Y will also keep changing...
N how the hck did u compare ln values via calc!?
Sry if it sounds rude
intution
😭
Say straight forward mam that we r taught for only 1st order yet 😂
Jk don't mind me
nah nah thts not the thing
intutively i think it will be first order
Beautiful intuition...hope u don't take it to the exams
See I can clearly even help u understand how u can't even say it's not first order using the table...notice the half life period...it will be at around 3.57 as ChX3 which lies somewhere just more than 1.5s...now after the next 1.5s it will get 0.25* the initial value i.e. 7.04 which isn't even true...so that's how things r done
Oh my bad well we don't even know the initial concentration of ChX3 wow🥲😭😂
isnt 3 M given
So ig what we just know now is we can only use the calculator find log a/t at each point and then if k remains the same then we may conclude yeah it's of first order
yeah i mean we could
3M is given as the value of Y and the change given is of ChX3
wait
oh yh
Try try if no other way is found we might ask @iTeachChem sir
iteachchem
Transcription requested by Shhh
I sure sure check it out at a higher temperature matlab what will happen to rate constant would increase that is the obvious thing One weird thing that could happen is that the first order could become zero and zero could become first but I don't know if that is what is happening मैंने detail mein देखा नहीं है try करेंगे देखो अगर कहें डगते तो सभी बताना
Nhin sir vo temperature is given for the c part of the question...I tried using that but just got Ea(1/T2-1/T1)/R= ln k1/k2
@iTeachChem sir bta dijiye nhin ho pa rha h...pehla question hin...
*92 ka pehla part hin
have you tried plotting on desmos?
Oh nooowh ky Mtlb ho skta h iska
Kl dekhenge sir good night 🥲🫡🙏🏻
Graph se toh kuch smjh nhin aarha h sir
Doesn’t this show first order?
Mtlb ho toh rha h bs negative of time m bs kese plot hogya that's the thing...or maybe aap hin at t=1 ko t=0 pr equate kr diyen honge
na na ignore the -ve time wala thing
see it says the conc is 4.5 x 10^-3 at t = 0, wahi toh plot kiya hai
Oh haan ol
*ok
Um...kl dekhten h sir ab...
Lekin ismein ky graph plotting aise kr ke hin ans niklega!?
As beautiful as the intuition did by this gurl
Let's stay on point please
Sir hum toh aise hin bolen then...vo bhi graph n unka intutions k baare m...if u say won't txt anything as such from the next time 🫡
Sir ek baar dekh kr bta skten h sahi h ya galat kyunki confusion abhi bhi thore bohot h like 85° C pr order yahan pr change nhin kiyen h hum but it might happen ki vo zero bn gaya ho or SMTH... moreover signs ka hum khaas dhyan nhin diyen cuz Ea ya k negative m ho ya positive m magnitude hin generally puchha jata h n?
