Relative Motion Doubt
Should we solve this question by taking acceleration of ant wrt ground or acceleration of ant wrt stick
76 Replies
@Gyro Gearloose
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i think it is given u wrt stick so tht only
there is no mention of ground , or stick hittin the ground , i think we should take it wrt to stick
if we take acceleration of ant wrt stick it is 0 cus velocity of ant wrt stick is constant
yes
but there will be psudeo force
So max height will be equal to the length of rod right?
ooh
wait nvm
V wrt to stick is 0 , ye
no psudeo force
ye
But the answer for max height is given as u^2/2g
what does it mean by max lenght , it gave no end point
yeah my ques is thers no height given of tower
so ...
how
will we knw how much the stick travelled
According to the solution of the question, acceleration wrt ground is g...so the the ant will be able to travel upto a particular height only...but I don't understand the reasoning behind that solution
wrt to ground tht will be g yes
makes no sense tbh , if it is constant wrt stick , it will always be constant wrt to stick , it can travel till end of stick
yesss exactly
lemme look this que up
the stick is accelerating downwards?
yes and initial velocity of stick is 0
uhm guys its from pw right
what chap?
yup
kinematics
and uh which like topic is it given under
relative motion
cuz pw gives soln videos
explaining
I have the video but I don't understand it
lemme loook
other
explanations
wait so shouldnt it be wrt ground
yeah
so whats your doubt lol
Filo
A stick of length L is dropped from a high tower. An ant sittin... ...
Solution For A stick of length L is dropped from a high tower. An ant sitting at the lower end of the stick begins to crawl up at the instant the stic
there is no definite end point
velocity of ant wrt to stick is fixed , it can travel the whole stick
yup exactly
lemme see
how ?
see the stick is going down na
so g will be applied on ant and the stick
so is ant , force on both is same , there acc is same , there is no relative acc
mass isnt same
so force isnt same
mb , i wanted to say a is same
yeah a is same
so it can travel the whole stick
but break it and then apply thinking of urself as the ant
wait
oh shi
@Percy its not talking abt the stick
and even if travels all the stick
lets just assume it travalled a height
could be the length of stick or anything
but since yaha ant pe bhi g hai
no , but i understand it now
what the question trying to ask ,
isilye one point pe aake uska velocity zero ho jaygea
its basically projectile motion if u kinda look at it
max highet = U^2 /2g
whats the ans @Percy
not relative to stick , relative to ground
this only
hn
frame of refernce ka concept hai
main
so max height wrt stick?
no
u is vel of ant wrt stick and 2g is accn of ant wrt to stick
, no acc wrt to stick is 0
oh hn
then 2g kaise
u^2/2g
2g what
u^2 / 2g , its the formula for max height when we throw something straight upward
can get that by energy conservation
oh
yeah
1/2mv^2 = mgh
what is wrong with this explanation?
nothing
according to that logic ant should be able to travel the entire stick
we were focused on stick , it can travel the whole stick , ye but wrt to initail hieght on ground frame it can only travel some max heigt
the question said stick is sufficiently long , which means ant can reach max hiehgt
I am so sorry but I still dont get it
ok so see
stick is comign down with acc g
ant is also coming down with acc g
ant has v wrt to stick
and initail stick velocity is 0
so ant was going up v , at t=0
its basically projectile
throw a ball up with velocit v and find max height
ohhh, so basically this entire time we have been trying to find the distance travelled by ant on stick but in reality we were supposed to find max height possible by ant
ye
the stick and ant was just there for throwing off
yeahhh that makes sense
thank you sooo much for the clear explanation
wait
dont close
kk
what do u mean by "max height "
stick is falling down
and so is ant
ant has velocity up v , and acc g down
so there will be a max height it reaches
max height on what
stick?
or wrt ground
on nothin , just wrt to its initial positon
as mentioned in question
initial position se toh gir hi rhi hai woh ant
"max" kaise hua fir
its not falling down , its going up , velocity v
first its going up
think of throwing a ball up , it has g down v uop
it goes up then comes down
and reaches a max height
if u throw a stick from a tower with ant on it then the final position of ant is def lower than initial tho
we aint even talkin abt final
imagine v = 100m/s
it will take 10 sec for gravity to make it 0
till then it will clim
if v = 0.2 , it will take gravity 0.02 sec to make it 0
till then it will climb max height
can I close it now
yepp
+solved @Gamertug
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