organic
here the ans is given 2 but acc to markonikov rule shouldnt it be 1 im getting confused
11 Replies
@Dexter
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Markovnikov? Did you mean Zaitsev?
Also, since F is a poor leaving group, elimination here occurs by E1cB mechanism, which goes like this.
1. Strong base abstracts proton, generating carbanion on β-C
2. Lone pair on carbanion shifts towards the α-carbon, forcibly removing the group that is attached.
The determining factor is stability of the carbanion. Here, we can't judge by the presence of -F since it's one carbon away for both possible carbanions. However, primary carbanion is more stable than secondary as there is less +I effect from connected alkyl groups. Hence carbanion is formed on the terminal carbon, and therefore, double bond is also formed there.
@Sephrina
oh ok thnks
but like this will happen in f only right?
In haloalkanes, yes, only for fluoroalkanes.
But it can also happen for other bad leaving groupd
ohh ok thnks
+solved @Opt
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