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iTeachChem
•
9mo ago
Aetherfly
Electrostatics / Mechanics
how
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I
iTeachChem Helper
•
4/12/25, 1:59 PM
@Gyro Gearloose
I
iTeachChem Helper
•
4/12/25, 1:59 PM
Note for OP
+solved @user1 @user2...
+solved @user1 @user2...
to close the thread when your doubt is solved
. Mention the users who helped you solve the doubt
. This will be added to their stats
.
A
Aetherfly
OP
•
4/12/25, 2:09 PM
?
A
Aetherfly
OP
•
4/12/25, 2:10 PM
ghost ping
O
Opt
•
4/12/25, 2:10 PM
Yeah
, I took components wrong
A
Aetherfly
OP
•
4/12/25, 2:10 PM
oh
A
Aetherfly
OP
•
4/12/25, 2:10 PM
can u explain how do I start
O
Opt
•
4/12/25, 2:19 PM
,rotate
T
TeXit
•
4/12/25, 2:20 PM
O
Opt
•
4/12/25, 2:20 PM
x is position of Q
, y is position of q
O
Opt
•
4/12/25, 2:20 PM
I started off here
T
TeXit
Click to see attachment
A
Aetherfly
OP
•
4/12/25, 2:22 PM
hmm
A
Aetherfly
OP
•
4/12/25, 2:22 PM
I got this differential eqn
A
Aetherfly
OP
•
4/12/25, 2:22 PM
but I dont know what to do after that
O
Opt
I started off here
A
Aetherfly
OP
•
4/12/25, 2:27 PM
does it require some subsitition
O
Opt
•
4/12/25, 2:27 PM
That
's what I
'm thinking
O
Opt
•
4/12/25, 2:29 PM
Ok
, yeah
, square both equations and add them
Take x
²
+y
²
= r
²
O
Opt
Ok, yeah, square both equations and add them Take x²+y² = r²
A
Aetherfly
OP
•
4/12/25, 2:30 PM
what does that do
O
Opt
•
4/12/25, 2:30 PM
Just a sec
, I
'm checking if it works
A
Aetherfly
OP
•
4/12/25, 2:30 PM
alright
O
Opt
•
4/12/25, 2:36 PM
Damn no
, it doesn
't help
A
Aetherfly
OP
•
4/12/25, 2:37 PM
sad
A
Aetherfly
OP
•
4/12/25, 2:40 PM
what if we try centre of mass
?
O
Opt
•
4/12/25, 2:40 PM
Oh wait it does work
A
Aetherfly
OP
•
4/12/25, 2:41 PM
oh
O
Opt
•
4/12/25, 2:41 PM
Ok
, so
, consider the point
(x
,y
) right
?
A
Aetherfly
OP
•
4/12/25, 2:41 PM
ok
O
Opt
•
4/12/25, 2:41 PM
Now
, it
's an imaginary point such that its x component is the position of Q
, and y component is position of q
.
O
Opt
•
4/12/25, 2:41 PM
These equations of motion we got apply to it
A
Aetherfly
OP
•
4/12/25, 2:41 PM
yup
O
Opt
•
4/12/25, 2:42 PM
But by squaring both and adding
, we get a single dimensional equation in acceleration and it
's position
A
Aetherfly
OP
•
4/12/25, 2:42 PM
yes
O
Opt
•
4/12/25, 2:42 PM
And once it
's a single dimension motions
, we can solve right
?
A
Aetherfly
OP
•
4/12/25, 2:43 PM
wait a single dimentional
A
Aetherfly
OP
•
4/12/25, 2:43 PM
ok yes
A
Aetherfly
OP
•
4/12/25, 2:43 PM
yes ong
A
Aetherfly
OP
•
4/12/25, 3:01 PM
ok so I got this
A
Aetherfly
OP
•
4/12/25, 3:02 PM
a
= b
/r
^2
A
Aetherfly
OP
•
4/12/25, 3:03 PM
@Opt
A
Aetherfly
OP
•
4/12/25, 3:03 PM
arent we deriving what we would get using energy conservation
?
Original message was deleted
A
Aetherfly
OP
•
4/12/25, 3:11 PM
whats a
O
Opt
•
4/12/25, 3:12 PM
No
, it
's a
=b
/r
²
O
Opt
•
4/12/25, 3:13 PM
But there is an issue
. We can
't take components
.
O
Opt
•
4/12/25, 3:13 PM
@SirLancelotDuLac I think you should take a look
O
Opt
But there is an issue. We can't take components.
A
Aetherfly
OP
•
4/12/25, 3:13 PM
what
A
Aetherfly
OP
•
4/12/25, 3:13 PM
why
A
Aetherfly
OP
•
4/12/25, 3:13 PM
we assume r to be a vecot
A
Aetherfly
OP
•
4/12/25, 3:13 PM
(x
,y
)
=
(r
, theta
)
O
Opt
•
4/12/25, 3:13 PM
Yes
, but our equation here is strictly for the absolute value
(length
)
A
Aetherfly
(x,y) = (r, theta)
O
Opt
•
4/12/25, 3:14 PM
Ok
, that
's not how it works
, just saying
.
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