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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Kyunki k is proportional to ln(conc/final conc)
and?
so k or t ka slope ho ya ln(ao/a) ka dono same hin honge.../
what
yes
what does that have to do with 3rd being wrong tho i dont get it
i mean when i solved i did get the y = mx + c form for the first one
but idk what to do with 3rd
mam said if 1st is correct the 3rd will be incorrect but i dont get how
could you please share the expression for total pressure (and hence, partial pressure of A?)
(hint: this is in ncert :)
its will be ln(p0/p0-p) = kt
pt = p0 + 2p
p = pt - p0 /2
okay so then what will the pressure of A be?
solving that we get ln (2p0 / 3p0 - pt) = kt
and ln (3p0 - pt ) = -kt + ln(2p0)
partial
what
tadaaaa
if 3po-p is linear then po-p cannot be, right?
ye but its inside ln , how can we be sure of it
thats what am asking
whaddya mean
i mean idk how can we be sure it wont be linear
I take the linear part back, thats not imporant here. the graph ln p0-p does not represent this setup
that is important
ye i mean what if it does
how can we be sure
that it wont
what if coincidentally its the same graph
slope cant be same na
even if it is linear
i can feel the intuition but is there any way to prove
desmos me plot it :)
iteachchem
Transcription requested by Mast Raho Yar
Can you share the pressure at any point in time t? What is the total pressure going to be? What is the expression for that? If you start with p not at time equal to zero, which means only a is present at time t, you will have some a that, you know, concentration come over here, then some amount of b and c are also found to account for their pressures, doing all of this similar to what you're doing in chemical equilibrium. What is the expression for p there? Think about that, and you'll get why which one is correct and which one's incorrect.