Q 106 Zumdahl Questions Solutions

@Shhh
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iTeachChem Helper
@Dexter
iTeachChem Helper
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
iTeachChem
iTeachChemOP2w ago
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iTeachChem
iTeachChemOP2w ago
Hope working sahi dali hai relevant to the q hah lemme know @Shhh
Shhh
Shhh2w ago
Mtlv I just tried giving it a shot....working um...itne saare datas n processes hin ek saath ho rhen then...😵‍💫 Yh relevant to the question only!datas sare sahi h
iTeachChem
iTeachChemOP2w ago
What data is missing?
Shhh
Shhh2w ago
Given question ke saare datas likh diyen h hum aise toh...n idk sir aap vo solution and approach dekhiye n flaws ho skten h kch jgh...
iTeachChem
iTeachChemOP2w ago
@Opt @SirLancelotDuLac wanna try?
Opt
Opt2w ago
This is scary af What do we need to calculate?? @iTeachChem
Shhh
Shhh2w ago
😂 Sir forgot to post that
Shhh
Shhh2w ago
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SirLancelotDuLac
Oh man, this is scary. For 105th on this one, the heat lost by uranium which is (a^3.rho.(200-28.5)*specific heat) must be equal to heat gained by heavy water.
Shhh
Shhh2w ago
Bhai 105 koi kr hin nhin rha h But well thanks for ur try n attempt
SirLancelotDuLac
Oh, well the thread was named 105th so I thought 😅
Shhh
Shhh2w ago
Yh that's even a typo Sir kch dekh kr btaiye n ya aage kaise badhna h ye btaiye...
iTeachChem
iTeachChemOP2w ago
You get volume of expansion by volume of the cylinder, then you need to find the moles of A. You have P (total P - aq tension), V (above) and T, so you get total moles. minus the moles of CO2, H2O you get moles of A. So far so good? To get moles of the compound, q/1893 (mcdT) yaha se ho gaya na?
Shhh
Shhh2w ago
sir shaam ko dekhenge sorry....currently kinda busy in another thing....sry Oh wow Ye toh completely different sa approach hogya sir😶 Hmm or ye v h ki jaise hum kr rhen then usse bs delta Hf of A hin aa pa rha tha max to max Nope sir...like ig we r missing something....pv/rt se yahan pr no. Of moles of x thori milega no. Of moles of H2O milega kyunki nichhe se upr thora sa compress hua...moreover agr V total diya rehta toh bhale kch kiya ja skta tha...tb fir cylinder k andr k volm ka idea rehta N idk ig 2nd question m bhi same hin sa kch face kr rhen h...possibly I m only interpreting the question in the wrong way ig
iTeachChem
iTeachChemOP2w ago
you will get moles of A na. you get moles of q from total heat evolved divided by 1893 :)
Cakey Bot
Cakey Bot2w ago
shhh122333
Transcription requested by Shhh
सर मतभब चिसे उपर पूरा सिलेणडर का हाइट नहीं दिया वा और फिर जितना volume displaced हुआ वो पता है और displaced हुआ तो उसको i guess water cover किया न तो फिर water cover किया तो फिर वोल्यूम दिया वा है और फिर water cover किया तो उस इसाप से उसका मोल्स निकलेगा i guess वोर्टर का
iTeachChem
iTeachChemOP2w ago
correct displace hota hai cos all the stuff is formed. so, CO2, O2 and A = 0.3, 0.25 and whatever A you get from n=PV/RT P = atmospheric P -31
Shhh
Shhh2w ago
Oh yh got it sir thank you anyways Lekin isse toh bs A kitne no. Of moles h ye pta lga what next!?
iTeachChem
iTeachChemOP2w ago
upar ja raha hai cos gases are formed from solid, total volume increases and water formed volume < gas volume empirical formula you have moles of CO2, O2, H2O and A and hence moles of C, O, H and A it is given that A is an element that is a gas, so it must be one of the halogens (cos reactive :D) or N you get mass of A, find density and whichever gas it is closest to that is the answer!
Shhh
Shhh2w ago
Ye reactive vala logic rehna mandatory h n...ismein toh ho ja rha h lekin aise toh bohot saare v ho skten h O2 hogya then I don't remember s8 gas k form M rehta tha ya nhin...moreover baaki dono m yahi n krenge ki 2nd m pv pv krke nikal lenge n 3rd m C delta T
iTeachChem
iTeachChemOP2w ago
S8 is solid

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