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@Dexter
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Hope working sahi dali hai relevant to the q hah lemme know @Shhh
Mtlv I just tried giving it a shot....working um...itne saare datas n processes hin ek saath ho rhen then...😵💫
Yh relevant to the question only!datas sare sahi h
What data is missing?
Given question ke saare datas likh diyen h hum aise toh...n idk sir aap vo solution and approach dekhiye n flaws ho skten h kch jgh...
@Opt @SirLancelotDuLac wanna try?
This is scary af
What do we need to calculate??
@iTeachChem
😂
Sir forgot to post that

Oh man, this is scary.
For 105th on this one, the heat lost by uranium which is (a^3.rho.(200-28.5)*specific heat) must be equal to heat gained by heavy water.
Bhai 105 koi kr hin nhin rha h
But well thanks for ur try n attempt
Oh, well the thread was named 105th so I thought 😅
Yh that's even a typo
Sir kch dekh kr btaiye n ya aage kaise badhna h ye btaiye...
You get volume of expansion by volume of the cylinder, then you need to find the moles of A.
You have P (total P - aq tension), V (above) and T, so you get total moles. minus the moles of CO2, H2O you get moles of A.
So far so good?
To get moles of the compound, q/1893 (mcdT)
yaha se ho gaya na?
sir shaam ko dekhenge sorry....currently kinda busy in another thing....sry
Oh wow
Ye toh completely different sa approach hogya sir😶
Hmm or ye v h ki jaise hum kr rhen then usse bs delta Hf of A hin aa pa rha tha max to max
Nope sir...like ig we r missing something....pv/rt se yahan pr no. Of moles of x thori milega no. Of moles of H2O milega kyunki nichhe se upr thora sa compress hua...moreover agr V total diya rehta toh bhale kch kiya ja skta tha...tb fir cylinder k andr k volm ka idea rehta
N idk ig 2nd question m bhi same hin sa kch face kr rhen h...possibly I m only interpreting the question in the wrong way ig
you will get moles of A na.
you get moles of q from total heat evolved divided by 1893 :)
shhh122333
Transcription requested by Shhh
सर मतभब चिसे उपर पूरा सिलेणडर का हाइट नहीं दिया वा और फिर जितना volume displaced हुआ वो पता है और displaced हुआ तो उसको i guess water cover किया न तो फिर water cover किया तो फिर वोल्यूम दिया वा है और फिर water cover किया तो उस इसाप से उसका मोल्स निकलेगा i guess वोर्टर का
correct displace hota hai cos all the stuff is formed.
so, CO2, O2 and A = 0.3, 0.25 and whatever A you get from n=PV/RT
P = atmospheric P -31
Oh yh got it sir thank you anyways
Lekin isse toh bs A kitne no. Of moles h ye pta lga what next!?
upar ja raha hai cos gases are formed from solid, total volume increases
and water formed volume < gas volume
empirical formula you have moles of CO2, O2, H2O and A
and hence moles of C, O, H and A
it is given that A is an element that is a gas, so it must be one of the halogens (cos reactive :D) or N
you get mass of A, find density and whichever gas it is closest to that is the answer!
Ye reactive vala logic rehna mandatory h n...ismein toh ho ja rha h lekin aise toh bohot saare v ho skten h O2 hogya then I don't remember s8 gas k form
M rehta tha ya nhin...moreover baaki dono m yahi n krenge ki 2nd m pv pv krke nikal lenge n 3rd m C delta T
S8 is solid