Binomial Theorem
cant figure out how i can successfully open the summation without killing myself with the sheer numberof terms
aise questions ki approach kya hoti hai??
20 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.You get these summations by differentiation/integration of (1+x)^n
ahh i see... my weakness...
ok well
how do we do this here then
For the first one, diff. wrt x
alpha would be considered a constant in that case??
Write down the expansion for (1+x)^n, and diff on both sides as many times as necessary .
You need to do this twice, once for the r term, and once for the r(r-1) term, from which you can extract r² term.
Then, set x = 1.
It's a function of n
For the second one, integrate (1+x)^n from 0 to 1 wrt x
n comes out to be 5 ig.
i must say i am very lost in this wth did you just tell me to do bro 💀
Reduction formulae are very helpful. You can also use integration/derivatives in some cases.
this is just painful atp ;-;
i see i see
Solving questions now. 👏
I've given up on this attempt lmao 😿
Same lol.
Just mugging in case atp
bro not trying to be rude at all but bhai bahot vichitra tareeke se likha hai ;-; kya step kidhar se kidhar gaye ho samajh hi nahi aa raha ;-;
Ah sorry my bad. Just gimme a minute.
I hope this is better.
yess
thanks a lot ji 🙏
+solved @Opt @SirLancelotDuLac
Post locked and archived successfully!
Archived by
<@964432960197632059> (964432960197632059)
Time
<t:1743736304:R>
Solved by
<@763645886500175892> (763645886500175892), <@1075951732460376214> (1075951732460376214)