Equipotential Surface
how to these types of questions?
tried taking Ex and Ey integrated both and just got xy in both
20 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.You can find the equation of V using -dV/dx=Ex and -dV/dy=Ey and find the orthogonal curve to that
d/dx is partial derivative wrt x
i did that got Vx = -xy and Vy = -xy
dont know how to proceed
hyperbole, what the the orthonal curves to hyperbole
what?
They want equipotential surfaces so equipotential surfaces are perpendicular to the potential curves
So straight lines for hyperbole
i dont quite understand that last part
acc to ans is C?
Yeah
its Given D
What
i dont understand the solution at all
Uh
Mb i thought equipotential lines are perpendicular to potential vector they are not
They are perpendicular to field lines
yes thats what i was thinking
Ok so they are integrating the field to get equation of potential and they got xy so on what curve they will be constant xy=c
ooh wait ic xy = constant
in this case both Vx and Vy were Xy but what if they arnt? @hithav
We would have to take vector sum and equate it to constant that will be the ans
ahh ic
thx
+solved @hithav
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