Rotational Motion

Shouldn't the acceleration of the bead on release be g as there is no other force acting on it?
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13 Replies
iTeachChem Helper
iTeachChem Helper•2w ago
@Gyro Gearloose
iTeachChem Helper
iTeachChem Helper•2w ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Opt
Opt•2w ago
Normal force?
SirLancelotDuLac
SirLancelotDuLacOP•2w ago
On the bead?
Opt
Opt•2w ago
Yes. Because there's a centripetal force inward, there's a response normal force right?
SirLancelotDuLac
SirLancelotDuLacOP•2w ago
But just after release there's no velocity?
Opt
Opt•2w ago
Oh wait i understood the setup wrong What is the horizontal axis??
SirLancelotDuLac
SirLancelotDuLacOP•2w ago
Ig that's just to show that the bead is in the line joining centers of the two rings.
Opt
Opt•2w ago
No, it says it rotates about the horizontal axis through P
SirLancelotDuLac
SirLancelotDuLacOP•2w ago
Isn't the situation like this?
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Opt
Opt•2w ago
Thank you
sans
sans•2w ago
I got alpha as 5g/19R 💀💀💀 Nvm my moi was wrong I got it
SirLancelotDuLac
SirLancelotDuLacOP•4d ago
Um...so should the acceleration of bead be g?

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