Rotational Motion
Shouldn't the acceleration of the bead on release be g as there is no other force acting on it?
14 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Normal force?
On the bead?
Yes. Because there's a centripetal force inward, there's a response normal force right?
But just after release there's no velocity?
Oh wait i understood the setup wrong
What is the horizontal axis??
Ig that's just to show that the bead is in the line joining centers of the two rings.
No, it says it rotates about the horizontal axis through P
Isn't the situation like this?
Thank you
I got alpha as 5g/19R 💀💀💀
Nvm my moi was wrong I got it
Um...so should the acceleration of bead be g?
+solved @Opt
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