Vectors, on a circular arc
I got the diagram, not the rest
22 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Yeah, the answer is right there. Take it as complex numbers or vectors.
Let OA be x component, OB be y component
also, slapping a modulus on the given OC condition gives some weird 1 = alpha^2 + beta^2 + alpha*beta*sqrt(sqrt(3) + 2)
Don't do all that.
hm?
of what
Oh wait nvm
It's AC 🤦♂️
Well, you can do it by vectors or ...transformations?
Ok, take OA and OC as basis vectors, and express OB.
Then swap stuff around to get OB
2D vectors.
Just taking OA = (1,0) and OC = (0,1) works out
ah
taking examples
:kekw:
genuinely good idea
No, just taking basis vectors lol
lemme try this
OB = (cos75°, sin75°)
2√2OB = (√3+1,√3-1)
ah brilliant nice
i got it
wtf have they done
Tf?
yea 💀
Why dot products?
not a clue
well i will safely be ignoring that monstrosity
thanks yall
Lol
Do that
+solved Opt SirLancelotDuLac
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