Organic chem doubt from hydrocarbon/ alkyl halide
Shouldnt there be a 3rd case as well in which H radical is removed from the left most carbon (1st carbon acc. to IUPAC naming)
21 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.The two carbons connected to the double bonded carbon are identical.
How
Theres a methyl group attached so the numbering of both the carbons is different
No?
shouldnt third nd fourth case be the resonance strucs of the two given compounds
Oh alright i get it
This is allylic bromination. Substitution takes place before resonance can occur.
Thank you for pointing it out. I do fail to see the obvious sometimes
Dw it happens to everyone.
@hardcoreisdead Free radicals generally do not undergo rearrangement/resonance structure change since they're too unstable to stay for very long. Reactions occur almost instantaneously
hamare sir ne toh karaya tha par
It can happen, but your product mixture is going to have a very tiny amount of the resonance structure product. Negligible amounts.
I reckon it can happen in cases where you have an extremely stable free radical that also has resonance. Which you're basically never going to come across
3 deg free radicals ??
Benzyl 3° might have such a case.
Look up a paper and check the values lol
Like free radical bromination of cumene or something ig.
Can't judge without the numbers.
exam mein kaise pata chalega lol
They can't ask unless its obvious to a high schooler
hmm point
they wont
Ye toh thoda high school chem ke realm se bahar ho jayega
solved?
Yup
+solved
+solved @Opt
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