EM Waves, magnetic field direction

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26 Replies
Nimboi [ping if answering]
I'm all confused here Here's what I assumed: Propagation vector is 3i + 4j from inside the bracket (c vector) Electric field vector is 4i - 3j (E vector) Doing c vec = E vec cross B vec (after assigning B = <p,q,r>) gives r = -1 and 4q=3p And if r = -1, it should be -k cap I didn't think that way in the exam, I just saw the magnitude of the E vector was = 5 so I marked the 5kcap option Which was somehow closer to the original answer 🤷 I'm lost
Nimboi
Nimboi•4w ago
@Gyro Gearloose
SirLancelotDuLac
SirLancelotDuLac•4w ago
Yea, your method is correct and that gives -5 k cap no?
Nimboi [ping if answering]
._. lemme check again
SirLancelotDuLac
SirLancelotDuLac•4w ago
ExB=(4i-3j)x(-5k cap)=20j+15i which is in direction of 3i+4j
hithav
hithav•4w ago
c vec=E vec cross B vec is kinda wrong no you have to compare only their direction vectors and then c=EB for the magnitue
Nimboi [ping if answering]
ok nvm, in my method i'm getting (4q+3p) kcap where q and p are unknown constants how'd you get from there to -5 magnitude toh i got, anyway 57/3*10^8 is the magnitude of all the options
SirLancelotDuLac
SirLancelotDuLac•4w ago
We have E=4i-3j and c=3i+4j so B must be along the z-axis. Now, either you can see by the right hand rule or just compare from options.
Nimboi [ping if answering]
all the options are along z-axis
SirLancelotDuLac
SirLancelotDuLac•4w ago
Yeah but use right-hand rule no? It gives you B is along -z axis.
hithav
hithav•4w ago
wait shouldnt the ans be C then
SirLancelotDuLac
SirLancelotDuLac•4w ago
And magnitude we know to be 5 ig.
Nimboi [ping if answering]
oh okay yeah i can use right hand rule on 3x+4y and 4i-3j
hithav
hithav•4w ago
how
Nimboi [ping if answering]
same question okay -z part i got
SirLancelotDuLac
SirLancelotDuLac•4w ago
Actually write the E-field as 5(number infront of given E-field) so as to get the unit vector for E. Now, the magnitude of B field is (5number infront of E-field)/c Direction of B-field is -k So now just write it as (number infront of E-field/c)*(-5k)
Nimboi [ping if answering]
oh shit wait some of the magnitude of the electric field is contained in the 4i - 3j that's the part i was missing and the spidey sense i had in the exam i.e. the magnitude of Efield is 5*57, not 57, since the magnitude of 4i - 3j is = 5 @hithav lance is this correct
hithav
hithav•4w ago
yeah
SirLancelotDuLac
SirLancelotDuLac•4w ago
Yep.
Nimboi [ping if answering]
thank god i went briefly insane over this bhery nice ques +solved SirLancelotDuLac oup
hithav
hithav•4w ago
💀 we need to up our level if we think this is a bhery nice ques
Nimboi [ping if answering]
naw naw its all good i learnt something thats all that matters
hithav
hithav•4w ago
now i hope a similar ques comes in mains and ppl get confused
Nimboi [ping if answering]
same >:)
trin
trin•4w ago
+solved @SirLancelotDuLac
iTeachChem Helper
iTeachChem Helper•4w ago
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