Hydrocarbons, Saytzeff/Hofmann product
The answer is Hofmann product here even though the base is small. I assume its because N(CH3)3 is a poor LG?
* Is N(CH3)3+ a poor leaving group? Why/why not?
* If it is, what decides whether 'small base' dominates or 'poor LG' dominates?
22 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.ig cuz it a bulky group
It is a poor leaving group and the reaction mechanism is E1cb
In E1cb We always get a hoffman product (most of the times i guess)
Small base bulky base is For E2 mech
isme mech hi alag hai
i had this noted down that NR3+, NO2, CN, COOH and SO3H always give Hoffmann as major product cause of strong -I effect which stabilises carbanion
wait could u give me a quick summary of favourable conditions and major products for E1, E2 and E1cb
E1 happens in mild acidic medium and requires heating and the reaction is carbocation based.
E2 happens in strong basic medium,requires heating and no carbocation or carbanion is formed.
E1cb also happens in a strong base,With a poor leaving group ,and Its a carbanion based reaction
ah ok, saytzeff and hofmann when for each?
E1 E2 saytzeff(mostly)
E1cb hoffman
E1 E2 mein hofmann kab aata hai
E2 mein with bulky base
alr this makes more sense now
E1 mein when the substrate is bulky
hm yeah cuz E2 cant function with a poor LG
that'd slow the reaction
yeah
Man i gotta go for the mock rn
ion wanna
😞
yeah yeah bet
lmao
aa jao deke
Yeah
merko toh sirf afternoon mein dena hai
i know my shift B)
hiw
oh
8th
B)
got it
hackr
ill revise E1cb, apply it to the question and then close doubt