stereoisomers

in the answer its given x=5 y=7 z=2 in the first one wont there be 5 structural and 3 stereoisomers so 8? and in the 3rd one if S is already specified then wont there only 1 possible product?
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13 Replies
iTeachChem Helper
iTeachChem Helper•2w ago
@Dexter
iTeachChem Helper
iTeachChem Helper•2w ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Opt
Opt•2w ago
Fractional distillation does not separate stereoisomers since their physical properties are identical As for the third one, how do you get an extra carbon? Is there a mistake in the print?
Augustine
AugustineOP•2w ago
ohhh
Opt
Opt•2w ago
Well, to be precise, optical isomers have the same physical properties. Geometrical isomerism is different, but that's not a thing for the first one.
Augustine
AugustineOP•2w ago
hm seems so maybe they forgot to add methyl in the reactant
Opt
Opt•2w ago
Yeah, so try adding that and doing it again.
Augustine
AugustineOP•2w ago
alr thanks hm then howd y be 7 im getiing 7 if we incude stereoisomers @Opt
Opt
Opt•2w ago
Huh. Yeah. That's inconsistent.
Augustine
AugustineOP•2w ago
i guess the answer key is just wrong for this one 😭
Opt
Opt•2w ago
That or we're cooked. @Dexter take a look
Dexter
Dexter•2w ago
If enantiomers banenge then the fractions will be same i guess and diastereomers mein alag fractions aaenge Very lengthy question goddamn
ns
ns•2w ago
x= 5, since 5 structural isomers are possible and each will be obtained separately. There won't be any stereoisomers for each of these isomers due to the absence of restricted rotatory system and chiral centres. y=7 - I'll draw it out and send later. z=2, the config of cl at locant 3 is fixed so the other one can be R or S. there won't be structural isomers here since the IUPAC name has been provided. Also, each of these cases, i.e., the RS one and SS one will each have an enantiomer. But enantiomers cannot be separated by fractional distillation so we count them as one fraction

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