beats
|f1-f2|=4 , f1= 200 given so f2 can be 204 or 196
|f1-f2'|=6 , f1=200 given so f2' can be 206 or 194
if f2= 204, tape lagake 194 tak dec ho gyi , 6 beat freq
if f2= 196 , tape lagake 194 tak dec ho gyi , 6 beat freq
where am i going wrong
16 Replies
@Dexter
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Tape can't change frequency that much
+-2 is fine
yeh kya baat hui
if f2 is 204, tape lagake 198 ho jayegi na?
only thing we know that f2 "decreases"
decreases to what extent is not mentioned
so it can become 194 too
Or else in every question of this kind you get 2 answers
how i think of this is
f1 is 200 and f2 has to be something tht gives 4 beats, so f1 can be 204 or 196
now if we take f1=196, then after putting tape, f2 decreases for sure, means f2=198, toh beats=198-196=2
now if we take f1=204, then after tape f2=198, beats= 204-198=6
so ans should be 204
am I thinking it wrong?
ans 196
😠ek cheez aati h woh bhi sahi se nhi lag rhi
arey yaar, im dumb, f1 toh fixed hi rahega and variation maine f1 mei krdi
f1=200 is fixed, tape f2 pe h toh uski freq either 204 or 196, ab iski freq decrease check krke dekhna ki 200 ke saath diff kahan 6 kaa aa rha h
since we know ki f2 decreases bc of tape, toh case1:- 204 se 206 case2:- 196 se 194, u solved it waise toh already 🙂
but f2 = 204 se kam hoke 194 bhi toh ho sakti hai which still gives 6 beats
see from wht i understand, the change tht occurs should be even, mtlb 4 beats se 6 beats jaane ke liye, freq of the tuning forks ko bhi 2 se increase ya decrease krenge , toh if f1=200,f2=204, agar f2 becomes 194, toh beats is 6 but uski khudki freq has decreased by 10
it cant decrease by that much thats the only explanation ortherwise in these types of questions you will always get 2 answers
+solved @hithav
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