Thermodynamics
In many questions, if constant external pressure was mentioned we took it as Irreversible process, but in this question they have mentioned const ext p + rev. So what's the drawback?
11 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.hey, basics are that rev, irrev etc are different paths
here, since process happens against const external pressure - it is irrev
also, dS = q rev /T irrespective of the process being a rev or irrev one since dS is a state function (just like dU and dH)
check my videos out on thermo if you have a doubt in the theory, they are soid
sir so const ext pressure doesn't only mean irr, it might also mean rev, though when one needs to find state func, rev/irr doesn't matter and if path func is being calc so we take as irr ?
const ext pressure means irrev :)
But that would mean compression
NOT expansion
so think about this question specifically, what info is relevant
Okay sir
i dont get it though why is dS being found? q is not asking for it
https://tardigrade.in/question/five-moles-of-an-ideal-gas-at-293k-is-expanded-isothermally-p6h624pt
.
ah ok
i didnt see this one :D
about state function, when you find dS system, formula is q rev /T
dude post one q on one thread
gets confusing otherwise xD
https://www.sarthaks.com/3496981/one-mole-of-an-ideal-gas-at-350k-is-in-a-2-0-l-vessel-of-thermally-conducting-walls
this process is reversible
the black bg one is irrev
since it is rev, dS sys + dS surr = 0
so dS surr = -3.37
again, for theory watch sessions
Thank you sir!
+solved @iTeachChem
Post locked and archived successfully!
Archived by
<@1245771182104510557> (1245771182104510557)
Time
<t:1742139204:R>
Solved by
<@1035556259417571408> (1035556259417571408)