thermal conduction

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45 Replies
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@Gyro Gearloose
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Dexter
Dexter4w ago
wow interesting I = -KAdt/dx but dt isn't constant I will be dq/dt im not getting the equations
Opt
Opt4w ago
Yum. I started doing it and got a second order DE Got general solution for one side. Need to solve for other side, input conditions
Dexter
Dexter4w ago
Im getting three d wale terms dT/dx in the RHS dq/dt in the LHS
Opt
Opt4w ago
Let me try from the beginning actually
Dexter
Dexter4w ago
can't find how to relate all these
Opt
Opt4w ago
Wait you took dT/dx into consideration? The rod has negligible heat capacity so I assumed its temperature can be ignored. Huh Yeah, then I messed up
Dexter
Dexter4w ago
the source and sink are at different temperatures so the heat flow should be through the rod as well
Opt
Opt4w ago
Yup tup *yup Crap I did all of this wrong
Dexter
Dexter4w ago
😭
Opt
Opt4w ago
Got this and all
No description
Opt
Opt4w ago
Curve which like charging capacitor in RC circuit for comparison. Which makes sense.
Dexter
Dexter4w ago
time and temperature ko leke differential format banana hai but idk what to with the dx
Opt
Opt4w ago
Since it should asymptote
Dexter
Dexter4w ago
interesting i see
Opt
Opt4w ago
$Sa$ is $m{a}s_{a}$
TeXit
TeXit4w ago
Opt
No description
Dexter
Dexter4w ago
yeah It does it'll attain a steady state when T1 = T2
Opt
Opt4w ago
Ta = Tb. T1 and T2 are initial values I didn't want to get confused
Dexter
Dexter4w ago
oh haan yesyes I can't get the equations to work
Opt
Opt4w ago
Wait, won't that temp be (T1+T2)/2 ?
Dexter
Dexter4w ago
why so?
Opt
Opt4w ago
Just checking. Nvm it depends on initial difference
Dexter
Dexter4w ago
i see
Opt
Opt4w ago
IT ALL HECKING COLLAPSED PRACTICALLY EVERYTHING CANCELLED Final answer I got was exponential decay $\delta T(t) = (T_2 - T1)e^{-\frac{KA(m{1}s{1}+m{2}s{2})}{m{1}s{1}m{2}s_{2}l}t}$
TeXit
TeXit4w ago
Opt
No description
Opt
Opt4w ago
All conditions are satisfied Afaik @hardcoreisdead pls confirm Because I didn't take temp.grad. into consideration @Dexter see if you got the same result
hithav
hithav4w ago
No description
Dexter
Dexter4w ago
ah ok dT = dQ/ms😞 😞
flower
flower4w ago
Newton's law of cooling
Dexter
Dexter4w ago
no Its conduction that was radiation
flower
flower4w ago
Ohhhhh right
hithav
hithav4w ago
yeah it's not intuitive i had solved a similar ques before so it was all bit easier :sweaty:
Dexter
Dexter4w ago
idk man im not able to solve good questions aajkal quality has Deteriorated alot
hithav
hithav4w ago
4 more days left after that you will get back your form ,even I don't get new kinds of ques i end up seeing soln after 10-15 mins
Dexter
Dexter4w ago
idfk if I'll be able to crack good questions anymore man Feeling very demotivated nowadays
Opt
Opt4w ago
You did the simple thing 🤦‍♂️ I did Ta, Tb individually and subtracted lmao
hardcoreisdead
hardcoreisdeadOP4w ago
Exact answer
No description
Opt
Opt4w ago
Yup, same thing. I just took LCM
hardcoreisdead
hardcoreisdeadOP4w ago
Your T2-T1 implies T20-T10 or inverse of that Explain the logic of this ques pls
Opt
Opt4w ago
There's a mod involved because of the integration
hardcoreisdead
hardcoreisdeadOP4w ago
+solved @Opt
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