complex numbers

how was this manipulation done
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9 Replies
iTeachChem Helper
@Apu
iTeachChem Helper
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hardcoreisdead
hardcoreisdeadOP2d ago
actual ques
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hardcoreisdead
hardcoreisdeadOP2d ago
pls share complete solution if u do get it
SirLancelotDuLac
SirLancelotDuLacthis hour
Take y^3 as common, now you have (x/y)^3+1 which is z^3+1 which can be written as (z+1)(z+omega)(z+omega^2), so you get y^3(x/y+1)(x/y+omega)(x/y+omega^2) Which is basically (x+y)(x+omega*y)(x+omega squared y)
CertifiedBrownMunda
Assuming omega as cube root of unity right? I don't know why they don't write it properly. Authors gotta understand that even fourth root and further have imaginary roots yaar.
hardcoreisdead
hardcoreisdeadOP8h ago
got it thanxx i am still not getting the required statments tho can u help wth that
CertifiedBrownMunda
Gotta put the values of x and y and simplify. Remember to use the properties of omega while simplifying. Try once again

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