my idea of limits is very poor but why is limit x tends to 0 [x sin(1/x)] 0?
i can write it as [sin (1/x)]/(1/x) , will the ' limit x-0 sinx/x=1 ' work?
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@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Both are different things. In sin(x)/x, as x tends to zero, both the numerator and denominator tend to zero. At the same time in xsin(1/x) only x tends to zero while sin(1/x) oscillates between 1 and -1 very quickly. When a value in [-1,1] is multiplied by a near zero value, it tends to zero.
ohhh-
Also on writing sin(1/x)/1/x is same as sin(a)/a where a tends to infinity. And sin()/(bohot bada number) tends to zero
i see
okay thank u
how do i close this again
iteachchem
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