33 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.So, you get y as some function of x with a arbitrary constant right?
yes
The y(1)=1 specifies a specific function in that family of function so that you get a value for the constant of integration C
It's called an initial condition
ohhhhhhhh
ahh sothey give uthe initial condition
for C
Once you find the specific function by plugging in x=1 and equating the expression to 1, you can input x=2 to get the final answer.
Yup
The more the number of arbitrary constants, the more the number of initial conditions required.
i see
thank you
The equation looks separable so it's easy enough.
yes
Got it?
yes
@Opt whats ths thing for identifying homogenous eqn
like he said on top its 1+1 and bottom its 2
so shuld top and bottom have same power
Do the simple thing just and just substitute x by kx and y by ky on the RHS
If all the k's cancel out, it's homogeneous
Yeah that's the same thing.
ahh
deg(numerator) = deg(denominator)
ohhh
i might be asking a gazillion doubts for 1 week (maths board)
It's fine.
wait
if i take anti log in 1st step
ill get a diff answer no?
wait can u take anti log thru addition
i think u cant
@CertifiedBrownMunda arent both these lines y=x?
Nope. Red one will be y=x (assuming slope is 1) and blue one will be y=-x (assuming slope is -1)
ohho righttt
wait it lies in -x axis plane is that why?
not really. It has to do with the slope of the line.
Are you comfortable with trigonometry @burrito ?
uh yea sure lemme see
So the red line will probably make an angle between 0 and 90 with positive x-axis. Slope will be tan of this angle. For y=x the angle should be 45 degrees
For y=-x, the angle will be 135. Tan135 is negative
ohhhhh rightt makess sense
thank you
No worries. No doubts are dumb doubts. Just put it in the doubts channel. Someone, if not me, will come to rescue. Happy learning
🙏🙏okay
yea please ask one doubt on a thread, and better to ping the doubt solver thing than ping folks directly :)
+solved @Opt
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