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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.4 oxygen atoms surrounding it, and Cr's oxidation state in this is +6 which means it has an empty 3d and 4s orbital
no other option except tetrahedral
there are no lone pairs in Cr to cause square planar
ans is tetrahedral
cr is in +6 here
that means for square planar geometry, lone pair is a must condition?
yes
2 lone pairs specifically
1 lone pair and you end up with something else
see saw yes
0 lp=Td
1 lp=see saw
2lp=sq.planar
ryt?
@Nimboi
yes
also
have fun
Thanks!
npnp
this is so cool...thanks!
but sq planar molecules are preferred by paired or low spin complexes
like [PdCl4]2- has 0 l.p. and is sq planar while [NiCl4]2- has 1 l.p. and is tetrahedral
i now remembered that d0/d10 configs. prefer tetrahedral shape and d8 sq planar
but then why's CrO4 2- tetrahedral too im a bit confused
and this is why coordination theory is taught separately afaik 💀
@iTeachChem can u clear my confusion please?
Chemistry Stack Exchange
What is the hybridization of chromium in chromate and dichromate ions?
I was recently reading about the transition metals and some important compounds of them. I came across a rather interesting diagram in my book... a tetrahedral structure for the chromate ion. The o...
then the reason nimboi stated at the start is wrong here?
iteachchem
Transcription requested by Nimboi
Well, this is not going to help, but this should not be taught in school. That's the short answer. The long answer is with molecular orbital theory.
oh what 🥴
from a hybridization POV was I correct?
school ke level pe mug vomit is easier. actual karan toh ye hai
about the hybridisation theory, I am not sure, have not invested too much time into this specifically.
What does jd lee say, any clue?
Very little.
Our sir told us this concept today through example of KMnO4, and he told us that it will also be valid in CrO42-
im confused on some things, also my memory of this chap is a bit hazy so bear with me if i ask some obvious stuff lol
What's GS, ES, TH, im assuming you're saying that foreign authors follow a different course of action than ncert to explain hyb of the some compounds? but doesn't jee adv also adhere to the texts of ncert too? dπ-dπ in sp3 while pπ-pπ in d3s? if Mn is in +7 then won't all electrons of 4s and 3d empty out too? is that oxygen donating between sigma and pi bonds?
some might be dumb doubts haha, that's why i tried dming you these instead but it didn't allow me so im asking here
GS is ground state
ES is excited state
TH is tetrahedral
in NCERT chapter of d&f-block, there is a line where it is given that in KMnO4, there is pπ-dπ bond
our sir says that in JEE Mains, NTA follows NCERT so we have to answer sp3 hybridization if it is asked
But, according to many professors and foreign author's books, it is revealed that d3s hybridization is more appropriately correct as it is an inner orbital
So, if it is asked in JEE Advanced, then if the options says d3s hybridization then we have to choose it
But, if geometry is asked, then both hybridization gives the same answer, that is, tetrahedral
Now, coming to why Mn in +7 has empty 3d and 4p orbitals, so our sir told that +7 is an oxidation state not charge
There is a difference between oxidation state and charge
Hybrid orbital form sigma bonds only except in benzyne
Hence, the four hybridised orbitals form sigma bonds with oxygen
and then, unhybrid orbitals form pi bonds on top of that
yea googling gives d3s only, i'm aware charge and O.S. are diff but oxidation is the loss of electrons isn't it and that's how i did all the ques of this chap, if an element lost 2e-, it's in +2 O.S.
Mn can only exist in +2 and +3 in nature thats why it is charge
but, Mn+7 doesn't exist in nature that's why it is an oxidation state and not charge
I wish we were taught MOT since everyone on stack exchange says hyb is an imprecise method, but im not sure if i'm equipped to learn it or it requires external knowledge as well lol
same, @iTeachChem sir thoughts on being able to self study MOT? any pre-reqs?
Check my videos. Made based on jd lee. Once you do that you can go read jd lee. NCERT in parallel of course
All you need to know is addition, subtraction, and basic complex numbers knowledge.
+solved @Prachi
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