calorimetry
5g ice at 0 C is mixed with 5g os steam at 100C. what is the final temp ??
my approach
converting all to same state at same temp ->
ice to water at 0C requires m(Lf) heat
therefore mix becomes 10g water at 0C +mLv+100ms -mLf
mLv+100ms -mLf will increase temp of 10g water
2msT = mLv +100ms-mLf
T= (Lv-Lf+100s)/2
and give 10g water at T
13 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.what are the values of L for ice and steam
not given 🤡
iirc steam is more
so steam will give m(Lv) energy to ice
which will cause the ice to turn into water
and whatever energy the steam lost will also make the steam turn into water right
or am i tripping
ill summarise my approach wait
converting all to same state ->
ice to water at 0C requires m(Lf) heat
herfore mix becomes 10g water at 0C +mLv+100ms -mLf
mLv+100ms -mLf will increase temp of 10g water
2msT = mLv +100ms-mLf
T= (Lv-Lf+100s)/2
and give 10g water at T
correct?
cant even comment cuz direct ans given is 100 C
80 for ice and 540 steam in cal/g
this will give 280C as final
where am i going wrong
think about this in terms of energy flow
steam becomes water, steam cools down to 0 degree celcius
mL for steam = 2700, mc deltaT for steam = 500
steam releases 3200 cal of energy in cooling down to 0 degree celcius and becoming water
now if you calculate mL for ice, its = 400 cal
the water (formerly steam) gives that 400 cal to ice to melt
and what we're left with now is 10 grams of water with 3200-400 = 2800 cal of excess energy
that gives delta T = 280 BUT we didn't account for water --> steam conversion
heating up 10g of water to 100 deg requires 1000 cal, so now we're left with 1800 cal of energy
but converting all of that water to steam requires 5400 cal, which is way above what we had
so the system's temperature stays at 100 degree celcius, with some of the water converted to steam with whatever energy is left and some that stays as water
5(540) is producing more than enough heat to get ice to water and then that water to 100°C but it won't have the energy to convert it into steam. so in the 5g steam some of it will get converted into water at 100°c to bring the water from ice to 100c and then the process will stop.
yeh exactly
god i love calorimetry
ok so 3.3g steam and rest water at 100deg C
big thanks for such elaborate explanation
+solved @Nimboi @hithav
Post locked and archived successfully!
Archived by
<@741159941934415883> (741159941934415883)
Time
<t:1740483015:R>
Solved by
<@717724055217635398> (717724055217635398), <@726641475080683522> (726641475080683522)