4 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.to find the volume of lost mercury we use density of mercury at 100C or 0C
taking 100 for now
340- volume of balls at 100 - vol of mercury at 100 = vol of lost mercury at 100 should work then??
340-85(1+gamma1 T) - 255 (1+gamma2 T) = 4.8 * (1+gamma2 100)/density of mercury at 0 should give the ans
but density of mercury at 0 toh di hi nahi
okay so you're basically right, but you dont need the density at 0C explicitly
just express the lost volume using the density at 100c cuzthat’s when overflow happens.
setup the equation with initial mercury volume, expansion of steel balls and expanded mercury and equate it to the overflow.