26 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Is it 3?
Oh wait nvm, my solution is flawed ig.
@Opt Can you please share the answer to this?
I don't have it 💀
It's a Challenge Question so no answers or solutions
I mean, the only relations I know about R and r absolutely do not give anything.
I feel it's gonna be a very geometric argument and imma be pissed when I realise it if i do.
Judging by the squares, area related
Yeah feels like herons formula use hoga
They've given 2s value too
Kahin na kahin to
Welp I tried to use $s.r=\Delta$ and $\frac{abc}{4R}=\Delta$.
SirLancelotDuLac
Inverse pythagoras theorem or smth?
What is s.r here?
Idt there's an inverse cosine rule
semiperi.*inradius
Yeah man then I have no clue.
Btw lance did you attempt IGMO this round?
No as I did not forsee it being in the midst of boards ;-;
But yeah, will try it some other time ig.
All I managed to do was get it into this form.
Which is symmetric and seems to have some AM-GM type properties. Almost.
I'm getting ans 3
Could be, I have no way of knowing.
I didn't do anything, but generally in such cases minimum values come at equality, till what I've generally seen. So i just got the ans by taking a = b = c = 1
I know it might sound stupid but i've seen many questions that have max/min values generally at equality
Although, Its hard to provide a proper solution for this
Yeah the minus signs were causing the problems as mentioned above
True, but that is not rigorous tho.
try using AM-HM
im getting 3 using tht
+solved @SirLancelotDuLac
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