21 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.in general how do i know that at that specific point 1st 2nd or 3rd maxima
Why are you doing these questions now lol? This is just the exact YDSE set up from Wave Optics.
But let me type out the answer.
i was doing phy galaxy of waves
Constructive interference, i.e., maxima, occurs whenever path difference is integral multiples of wavelength, ∆x = nλ. But, ∆Φ= (2π/λ)(∆x), right? So, constructive interference is whenever ∆Φ = 2nπ
When n = 0, you get the central maxima. Your immediate next maxima is n=1, so ∆Φ=2π
if i am asked the location of 3rd maxima how can i do that
third maxima after central maxima means n=3
what point will it be on the line of pq
You will have two third maxima, one on either side of central maxima. One will be below Q, one will be well above P.
Just look up YDSE in wave optics if you have any confusion.
how do i know their location tho
y = nλD/d
Go watch a video on YDSE pls.
All your doubts get cleared
you'll learn more about this in Wave Optics lol you can skip it for now
hang on
this isnt exactly YDSE
the distance between the slits/speakers is definitely not negligible compared to the distance between speaker and screen
cant use those direct formulae i assume
Oh wait yeah
will have to derive stuff from angles
Nvm
Just use Pythagoras
you'd still be better off studying wave optics and YDSE before doing this ques tho
all of that is in 12th tho
am 26tard (11thie)
YDSE
sound mein kabhi kabhi miljaate aise ut patan sawaal
chill
alrr
thanx everyone
+solved @Opt
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