Physics (coulumbs law) doubt
Isme why have we integrated with integral limits from 0 to q. Kyuki ring hai toh -q to q nhi karna chahiye integrate?
20 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.No, the charge is purely positive.
Think of it this way. When you haven't gone even a tiny bit around the ring with your dl element, there is zero charge. Once you go the full circle, you have q charge. So the charge is 0→q
I don't understand. What do you mean by once you go full circle you have q charge @Opt
Ok, this is Cengage na?
Yeah
I see the issue
You see, dq = λ(adθ)
If you get that
Alright
Where theta is not the angle there, but the angle subtended by the element at the center of the ring
Think of it like that
Each charge element is actually a tiny bit of charge on an element of the circumference of the ring
Now, when you're integrating all the circumference elements, you're basically integrating the charge right?
Yeah
So, instead of taking the length elements, the publishers have taken the charges on them as charge elements.
Now, consider taking it as length on the circumference. You go from 0 length on the circumference to the total circumference of the ring, which is the same as 0 charge to total charge
Oh I see
It seems more complicated, but it's the same.
It's also more generally applicable.
Thanks I get it now
Is that it?
Yup
Then close the thread please.
It gets crowded
If your doubt is cleared write +solved @user who solved it, thank you
+solved
+solved @Opt
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