fluid dynamics
shown is a container of height H filled with water. it has two holes with length as shown . when water flows from both holes it strikes on the same point on ground. which is bigger x1 or x2
13 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.its obvious that v2>v1
however on equating range i got H=x1+x2
how does that make any sense
v1= (2gx1)^1/2 , t1 = (2(H-x1)/g)^1/2
v2= (2g(H-x2))^1/2 , t2= (2x2/g)^1/2
v1t1= v2t2 gives H=x1+x2
yes i got same
so that means both are the same points ig?
but you cant determine if x1>x2 or vice versa
but if both are same v1=v2 ho jayega
ha
range of water projection =
2 sqrt(h * (H-h)), where h is the depth from the top and H is the height of container
so x1 * (H - x1) = (H-x2) * x2
which means x1 = x2 innit
symmetry
@hardcoreisdead
do you have a given answernot as of now
test mein aaya tha dont have a key
x1=x2 ho gya toh v2>v1 nahi ho payega
v2>v1 might be wrong tho
nahi ho jayega
because
x1 * (H - x1) = (H-x2) * x2
Hx1-x1^2=Hx2-x2^2
(x2-x1)(x2+x1)=H(x2-x1)
this eqn has 2 solns , either H=x1+x2 or x1=x2
correct?
Yup
it should be OR or AND ..
yes so they're either the same point or x1 = x2
why not?
2nd hole is at a lesser height, so to traverse the same distance as the 1st hole before gravity catches up to it, the water needs to go faster
hence v2 > v1
yeah baadmein realise hua
+solved @Nimboi
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