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@Apu
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how? what?
4 unknowns, 3 equations and they solved it?
i guess the collinear points condition is the 4th equation to solve for all 4 unknowns but also i'd rather commit seppuku than solve 4 equations in an exam
I'm getting z =0 OR a=1
If we choose z=0, we get x=1
y=1 is always there
how are you getting z=0 or a=1
i assume we can't pick variable values and solve the remaining
since that's a little illegal
Mb, a=5 or z =0
how bru
as in where are you getting the values from

FRACK
NO WAIT
a=3 or z=0
That should be (-3+a)z=0
I'm effing dumb

So choose z=0 as your condition and proceed
Sub in another equation, get x
@Nimboi
wait back up
what was your first step
this was my main doubt
a not equal to 3 is fine and all
but what then
Gimme a bit. I'll write it down neatly and send.
oke
the information i derived from the question was
i) unique solution - the coefficient determinant not equal to 0 => a is not -3
ii) collinear points - i equated the slope of point A and B to the slope of point B and C
which ended up in me getting the equation of
a^2 - q^2 = (p - a)(q - p)
im just using p,q,r instead of x star y star z star for convenience
yeah i got nowhere from thereIt's actually -3. My calc is so bad today
Basic algebra going weong
-3 yeah its all good
i got -3
what was wrong here
what thought did i skip
amazing how the brain is capable of learning things like calculus and quantum physics and still stumbles on basic arithmetic half the time

Those are technically the star values
But whatever

@Nimboi Got it?
oh
you can do that?
manipulate LHS and RHS at the same time?
Wdym? The augmented matrix?
yes
i have somehow like never seen that
That's exactly how you're supposed to do it...it's basically adding and subtracting the equations
You don't add just the LHS of an equation do you?
You add both sides.
Basically that, but without the nasty variables and plus and minus signs getting in the way
oh
oh well
i might be dumb
Nah
Just go watch a couple Khan Academy vids. They're pretty good when it comes to this topic
Search for RREF
ah nice okay
Reduced Row Echelon Form
Or Gaussian Elimination
Same thing
pretty cool
thank u :>
+solved @Opt
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