Closest distance of approach due to Magnetic Field of wire
Consider an infinite wire carrying current I and a particle of mass m, charge q and at a distance a from the wire move with velocity v parallel to the direction of current. Due to the magnetic field, the particle gets attracted to the wire, and it turns around at a distance x. Find the value of x.I don't get the mathematical approach we should take in this question. I tried qv_xB=mv_ydv_y/dy and so on, but it doesn't give a clear answer.
9 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.RHS can also be written as m(v_x)dv_y/dx right ?
That would give answer after integrating
Can you send the complete solution?
'Cuz I'm genuinely at zero about where to start from and where to go.
Why would the upper bound be -v? Doesn't "turn around" mean velocity in y-direction is zero and changing sign?
when velocity in y direction is 0 and changing sign all the velocity will be in x direction and it would look like taking a left turn instead of turning around
Oh I see.
Well, thanks a lot, dude.
+solved @hithav
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