I
iTeachChem2mo ago
trin

capacitance

how to approach this q? i found charges on each capacitor but which charge do we use for finding the capacitance
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29 Replies
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@Gyro Gearloose
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trin
trinOP2mo ago
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SirLancelotDuLac
Cylindrical capacitor formula works here ig.
trin
trinOP2mo ago
but how to do it
Opt
Opt2mo ago
I got a different answer for some reason I tried converting to equivalent circuit.
SirLancelotDuLac
There are 3 capacitors out of which AB and BC are shorted so consider CD and D and infinity as capacitors in parallel
Opt
Opt2mo ago
Oh I forgot D and infinity
SirLancelotDuLac
Ah no I think I messed up...
trin
trinOP2mo ago
im getting option a
SirLancelotDuLac
We would consider this right? Because I'm getting the answer as nota for some reason.
Opt
Opt2mo ago
I got 8/7 πϵa
SirLancelotDuLac
Considering CD and D-∞, there is 48πϵa and 16πϵa in parallel so 64πϵa maybe? I think I need to revise this :sweaty:
Nimboi
Nimboi2mo ago
just a side point that's been tripping me up about this question but my teacher told me that charge induction only happens from the inside shell to the outside shell?
SirLancelotDuLac
Yeah, because the net charge inside closed conducting surface must be zero.
Nimboi
Nimboi2mo ago
so that means shells C, B and A can't acquire a charge? and thus can't acquire a capacitance? i suck at this chapter bro
SirLancelotDuLac
No they could acquire charge, the potential would be 0 at earthed places.
Nimboi
Nimboi2mo ago
oh charge flow is simply because of pot diff
SirLancelotDuLac
Yep.
Opt
Opt2mo ago
Is this not the equivalent circuit?
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SirLancelotDuLac
Ye. AB,BC are shorted so its just combination of two parallel capacitors? Oh I think I did calc errors but still Im getting A.
Opt
Opt2mo ago
Ok, I got B But my method was stupid to the extreme. Or maybe the question was intended to confuse. Idk Basically, the primary rule that governs charge distribution on conducting shells is that the field inside the shell must be zero. And it is already zero because the charge is uniformly distributed on D. Whatever in inside, is utterly useless. There is no need for a charge to be induced on any of the inner shells. So the only capacitance is between D and ∞ *net field
SirLancelotDuLac
There is field on the inside tho right? (Like C is at 0V and D is at some other voltage so field exists b/w C and D)
trin
trinOP2mo ago
i think the answer should be a tho
trin
trinOP2mo ago
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Opt
Opt2mo ago
Gauss' Law says no field.
SirLancelotDuLac
Is it wrong to say there is field between inner surface of D and outer sirface of C?
Opt
Opt2mo ago
There isn't any charge on the inner surface of D though? It's on the outer surface
SirLancelotDuLac
Ah I see.

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