Kinematics
I don't understand what it means by radius of curvature at pt of projection and how to calculate it
17 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Radius of curvature is just v²/a
What
That makes no sense
Is there any derivation of it
okay so when you project your object
just pick any point
hang on ill just send a picture
basically at the point of projection, if you took some very close neighbouring points and then connected them into a circle
what would be the radius of that circle
Ik that
I am asking how is it v2/a
it seems related to circular motion
mv^2 /r
v^2 / r
maybe something like that
@Opt do you have a derivation
oh
Oh Yr I got it
a = v^2 / r
Ye
r = v^2 / a
fair enough
Ok I try solving it
My ans is not matching
R= v^2/a(perpendicular) is a better way to represent
Oh yeah it is. 🤦♂️
Because you need to represent v as a tangential component to your circle of curvature, and consider the radial component of acceleration