Doubt regarding free fall of block in inclined plane...
"Find acceleration (a) of Inclined plane, so that Block (m mass) will free fall",, now wherever I see the answer, it's always "For free fall N = 0, so ma sin theta = mgcos theta"...
My doubt is that, to free fall a block, all you need is mg, right? So, why only N = 0, ma should be = 0 also.. even, N should cancel ma.. so that only mg remains.. but if we do N=0 its just Normal force being 0, the horizontal acceleration remains there.
I think N = mgcos theta should be answer.. but it isn't
7 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.I think free fall essentially means there's no other forces except gravity are acting on the body
If the normal is not equal to 0, then friction will act on the body and it won't just be gravity
whether its mg/2 or 3mg/4 or whatever other variation, as long as its just the gravitational force its in free fall
Yeah,, it should be just the Gravitational force to be in free fall, thus i think Normal as well as the f external would be 0
Why is f ext no 0, infact f ext= ma,, so ma sin sin theta = mg cos theta? I dont understand this equation
sorted?
Oh yea, its done sir
+solved @Nimboi
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