kinematics

water drops fall at a constant rate from a nozzle fixed height h above the ground. when first drop hits the the ground, at that instant nth drop begins to fall. find distance of 2nd and 3rd drop from ground at this instant idk the ans since i made this question myself.
33 Replies
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hithav
hithav2mo ago
you have to define the dimensions of the drop or else I don't think it will be possible to solve
hardcoreisdead
hardcoreisdeadOP2mo ago
idts thats necessary , i took this from kinematics mains pyq
simplybear
simplybear2mo ago
oh yea ive seen alot of these but i hate this i never get it
idk either
idk either2mo ago
chatgpt solved it well
hardcoreisdead
hardcoreisdeadOP2mo ago
the feelings mutual dont trust ai
idk either
idk either2mo ago
i checked it, everything made sense
Opt
Opt2mo ago
I got an answer $( \frac{2}{n}-\frac{3}{n^{2}} ) h$
TeXit
TeXit2mo ago
Opt
No description
idk either
idk either2mo ago
i think the q asked individual distances of 2nd and 3rd drop from ground, not distance between then
hardcoreisdead
hardcoreisdeadOP2mo ago
yep pls post your soln tho
Opt
Opt2mo ago
Oops. Yeah, let me do that
hithav
hithav2mo ago
No description
hithav
hithav2mo ago
:sweaty:
TeXit
TeXit2mo ago
No description
idk either
idk either2mo ago
gpt doesnt count the nth drop in sqrt(2h/g), i guess depends on the question's wording?
Ace007
Ace0072mo ago
time between drops sqrt(2h/g) / n-1 nhi hoga? cuz nth drop release hui hai, not hit ground
hithav
hithav2mo ago
It's time between releasing of drops
Ace007
Ace0072mo ago
for example 4 drops hai..time between 1-2, 2-3, 3-4....3 intervals hue na
Ace007
Ace0072mo ago
No description
Ace007
Ace0072mo ago
,rotate
TeXit
TeXit2mo ago
No description
Ace007
Ace0072mo ago
this will be distance of 2nd drop from ground
hardcoreisdead
hardcoreisdeadOP2mo ago
u time of flight of kth drop as time it took for first drop to reach ground - time it took for kth drop to move from nozzle right?
hithav
hithav2mo ago
Yes :sweaty: I am getting confused now
hardcoreisdead
hardcoreisdeadOP2mo ago
yeah intervals n-1 hue but we are concerned about total time , total drops and rate of falling
Ace007
Ace0072mo ago
n-1 intervals ko hi toh total time i.e, root 2 h/g laga hm i mean we hv to find time between releasing drops right...say n=4, so first drop and second drop me 't' time ka diff tha..then 2nd and 3rd me bhi 't' time...3rd and 4th drop me bhi 't' time tha...so 4th drop jab release hui tab 3 time intervals the na...and we know that tab first drop reached ground..so 3t = root 2h/g
hardcoreisdead
hardcoreisdeadOP2mo ago
hm makes sense
hithav
hithav2mo ago
👍
ishn
ishn2mo ago
so the time travelled for 2nd drop is root 2h/g - root 2h/g(n-1)?
hardcoreisdead
hardcoreisdeadOP2mo ago
t = sqrt(2h/g) (time for one drop to reach the ground) r = n-1/t (rate of drops coming out of the nozzle) time at which the 2nd drop falls = 1/r time at which the 3rd drop falls = 2/r distance travelled from top = g/2 (t)^2 => from ground = h - g/2 (t)^2 time of flight of 2nd drop = t-t/n-1 time of flight of 3rd drop = t- 2t/n-1 yes ig
ishn
ishn2mo ago
prolly equate that and subtract from h

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