Diff. eq.

No description
11 Replies
iTeachChem Helper
@Apu
iTeachChem Helper
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Nimboi
NimboiOP2mo ago
They did this using the homogenous wala method What I did was dy/dx = x^2 + y^2 / 5xy = x/5y + y/5x which means dy/dx - 1/5x * y = x/5 *y^(-1) this is a bernoulli's DE reducible to linear however, this doesnt seem to be giving me the answer
SirLancelotDuLac
Seems correct ig.
Nimboi
NimboiOP2mo ago
uhh alr ill try again to clarify both the functions become multiplied with (1-n) right, which would be 2 here along with the function in the integrating factor
SirLancelotDuLac
Multiplying the whole thing by y right?
Nimboi
NimboiOP2mo ago
yep i'm getting {y * x^(-2/5) = x^(8/5) / 4 + C} at no point is a modulus even involved as the options seem to suggest
SirLancelotDuLac
Modulus wala thing I'm guessing comes from the logarithms during the solving. Ah I messed up didn't I? The integral portion will be (x^8/5)/4*x/mod(x) or smth
Nimboi
NimboiOP2mo ago
yeah nvm i goofed up by putting y instead of y^2 not a very good day for my brain today thank you +solved @SirLancelotDuLac
iTeachChem Helper
Post locked and archived successfully!
Archived by
<@717724055217635398> (717724055217635398)
Time
<t:1737549977:R>
Solved by
<@1075951732460376214> (1075951732460376214)

Did you find this page helpful?