11 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.They did this using the homogenous wala method
What I did was
dy/dx = x^2 + y^2 / 5xy =
x/5y + y/5x
which means dy/dx - 1/5x * y = x/5 *y^(-1)
this is a bernoulli's DE reducible to linear
however, this doesnt seem to be giving me the answerSeems correct ig.
uhh
alr ill try again
to clarify
both the functions become multiplied with (1-n) right, which would be 2 here
along with the function in the integrating factor
Multiplying the whole thing by y right?
yep
i'm getting
{
y * x^(-2/5) = x^(8/5) / 4 + C}
at no point is a modulus even involved as the options seem to suggest
Modulus wala thing I'm guessing comes from the logarithms during the solving.
Ah I messed up didn't I?
The integral portion will be (x^8/5)/4*x/mod(x) or smth
yeah nvm
i goofed up by putting y instead of y^2
not a very good day for my brain today
thank you
+solved @SirLancelotDuLac
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