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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.looks active, no plane of symmetry
the 2 carbon atoms at the side are chiral because the molecule isn't symmetric
what about Cos?
bro cant tell if it is optically active or no
oh i didnt think about that
yes
cant tell without bridge and dash
of Me and H
optically active hai
upar neeche hai na
how does COS work again?
nahi hai COS
bridge and dash matters
Same thing hoti hai
unless he means
upar matlab bridge
that upper one is on other plane
neeche matlab dash
final verdict?
@Dexter ye so how does it not have a COS
if we pick the midpoint of the lower side, then both methyls are at an equal distance
so are both the hydrogen
Because CENTRE se pass nahi kar rahi
C E N T R E
ah, oke
lmao
fair
ðŸ˜ðŸ˜
optically active
Cos across the molecule
hota hai
yeah got it
matlab like cos should be an atom on the molecule?
2 atoms
in a molecule
jese isme
wot
deleted
oh wait
haan i sent it wrong
these are my notes
isme centre se pass kar raha hai na
Centre of symmetry is the line passing through centre and joining two opposing groups
got it that compound is active only
yeah
thanks
no problem
+solved @Dexter @Nimboi @Gamertug
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