Capacitors
what i did was total charge is Q(K+1) when capacitors conncected in parallel and since both are identical with same Dielectric charge will divide equally
V = Q/C
V = CV0(K+1)/2C = V = 550 but ans is 55
he is also gettign same eqn as me but he has dielectric also in denominator i understood his way but why cant we divide charge
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@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.we can divide charge finally but in the initial condition when the capacitors are about to be connected they will have different charges because one is disconnected from the battery and then given the dielectric slab and in another it's still connected to the battery when we give dielectric slab
ye ik charges will be KQo and Qo but its asking common voltage of Combination
so it will divide equally
Charge on each = Qo(K+1)/2
then V = Q/C
V = CVo(K+1)/2C
V = Vo(K+1)/2 = 11x50 = 550
not getting ans
capacitance will change right
C'=kC
both capacitence are kC
so it gets cut
no no
in the numerator you are just taking total charge/2
that would be KC+C/2
and in denominator it would be kC
ok got it solved
+solved @hithav
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