74 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Show us what you've tried, na?
Bhai kuch as such idea nahi lag raha
But one thing that did cross my mind is
When the support would move down would there not be slack in the string?
That's one thing
The other that came was when the support would move up, would there be a pseudo force on the bob? Would the small amplitude of the oscillations cause any pseudo force at all?
,rotate
Hmm..Wierd question.
I did a lot of approx and got Ļ(resultant) = ā99
Angular frequency won't be constant na?
nah dude option hi nahi hai
Unless you parametrise and grind trig, you won't get anything I think.
Trigonometry:???
idhar???
how???
where???
why????
....it's SHM . There is always trig.
sabse pehle to why????
Ig they are just asking the order maybe of the change but idk
valid
Wait, is this a spring pendulum by chance?
Might simplify it if all oscillations are in the same direction.
nope simple pendulum
given in question
simple pedulum
Oh yeah
....I ain't trig bashing this
Is the answer 10^-1?
nah dude
Ah. What is it?
1
10^-3
reverse engineering the problem
??
Ah wait yeah...
This basically
but order me unit thodi daalenge
...what?
har option rad/s me hai
plus order ke questions me order daal dete hai na??
OH
OH GAWHDAAMN
I JUST CHECKED OUT THE SOLUTION DUDE ERROR ANALYSIS
Send soln.
bhai aapne kara kya hai š
Basically (heavily questionable) but effective gravity ka concept
again they make shit solutions but yea
Ah it was fractional change..
i see i see
haa yaar ye to idea aaya bhi nahi ki ho sakta hai ye
š
but idhar
Actually omega won't be defined tho for such a condition as it is no longer an SHM maybe
w kiska hoga??
of support or bob??
Pendulum (Bob)
It is, just not simple to express.
goteem
It is just a composition of an angular and a linear SHM
This is your equation.
intresting
It's just a whole ton of trig bashing.
Wait the angular one gets affected by the linear one no>
achaha one question in this
It can be split into two oscillations along axes.
r vector ko aapne sin(10t) , 1-cos(10t) likha hai
One is simple, one is a composition.
1-cos(10t) kaha se aaya
Assume downward is positive.
length-height
That's your y from origin
Ohhhh okok
Key word being angular, pendulum goes (tho very little) but a vertical distance too right?
Yeah, that's why there's the 1-cos term.
In the FOR of moving origin, the pendulum is in regular SHM.
Oh wait
With time variable gravity?
And non constant omega?
Omega becomes time variable. Crap.
im lost atp what are yall going on about š
In combi of 2 shms, shm we get only in certain cases iirc.
When omega for both combi is same or smth right?
Or integral multiple
Not integral multiple also ig.
Ye nvm.
No, it'll be SHM for certain moments i feel, that's about it.
That would just give some zig-zagish oscillatory shape
Like sort of sine curvish maybe?
But anywho, question mein omega is non constant so maybe controversial š¤
nah more like a one sec
Yeah let's stay out of it
nah chodo nahi ban raha
anyhow thanks yall
ok i feel dumb question but delta g 2Aw^2
kaise hai?
Ig this is what they intended. (Order is 10^-3)
got it thanks
....
Ig they are talking about the maximum change in g, which is (g+w^2A)-(g-w^2A)
if im interpreting this right
The change is as such right?
Just confirming this stuff I want my concept to be as hard as Cabo Fibah
w^2A is verical.
mains when they try to act smart smh
Sawaal aisa banao ki samjh hi nahi aaye karna kya hai
ohhh from the support ka oscillations??
+solved @SirLancelotDuLac @Opt
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