40 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.bad attitude
no one send him a solution until he tries and struggles
man nhi kr raha switch subjects or take a break, try again tomorrow
phir bhi nhi aaya then read your notes or go back to core concepts
bhai question dekh ke samajh to aaye ki karna kya hai
isme to kuch idea hi nahi ho raha move kaise hoga
have you tried displacing the small mass by some small
x and then drawing all the forces on it
my SHM lil rusty
trying rnyea but usse kya hi nikelga
kx ke against ya along
koi sa bhi force nahi hai
just T and mg
wo to vertical me hai
subah se SHM aur Trigo leke baitha hu dimaag chalna hi band ho gyaa hai
is it (3)?
bru momento
bro left my curiosity hanging and went offline
yeah that never works
do all 3 subjects everyday
ek minute book kho gayi
if you can feel your brain getting exhausted
then leave the subj
no dude doesnt work that well for me
i tried
o ok
but do this then
it ended up with me not being done with ANY of the things
yea yea i wan about to but then socha ye puch leta hu bas
i was gonna read inorganic
answer to bata di jiye
YEA DUDE 3 HAI
nice alr
so the trick is
how to du
you'll need to go back to how the time period formula was derived
because in this case the restoring force is not only gravity, but also the spring force
The Brain Filler
YouTube
Deriving The Period Of A Pendulum Using SHM
This video uses forces and simple harmonic motion to derive the period of a pendulum (for small angles). It also shows why the formula only works for small angles.
OH
OHOHOHOHOHOHO
DAMN
THATS SO BEAUTIFUL DUDE
SO
nice question i like 👌
AGAIN ENERGY CONSERVATION TYPE KUCH KARNA HOGA IG
not required
ok ill leave some spoilered hints
look at it in the morning after trying
or now i mean im not your mom
bhai humne to bas
torque equate kara tha
refer to video to understand
along the direction of the restoring force he mentioned, the force you'll get is mgsin(theta) + Kxcos(theta)
you can get sin theta and cos theta by drawing the triangle of x and L when its displaced by theta, substitute values of sin and cos
now since x is a very small displacement compared to L (because SHM), you can write the sqrt(L^2 - x^2) term as just L since L>>x
which means you get the force as x(mg/L + K), which means the acceleration is x(g/L + K/m), which is equal to omega^2 x
and time period = 2pi/omega so compare and find
ok so uhm i saw the vid lemme read tese spoilahs tommorow dude m brain is fried 💀
yeah yeah
no point doing a question if your brain is fried
good work comrade
rest now
idk why mains ka SHM and Advanced ka trigo karne me mera itna time gaya and ita thak gaya
im a simple man
i hear advanced trigo
i skip
Pinworthy.
Aaaaaaaaaaa
Suits your pfp
Ye kya hua bhai 💀
Kindly ignore my messy work but bhai like you said we have to rederive the Time period ka formula...
kx cos theta kaha se aaya?
you're close
but the direction of
kx will be along the spring na
horizontal
toh the restoring force component of kx will be kxcos(theta)Pakka it will lie along horizontal? As in perpendicular to T?
Aachcha haa it will be horizontal
Sori diagram ke chakkar me sahi se socha nahi
torque use karlo
Yes yes
Got it
Proper solution
+solved @Nimboi
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